Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

Inverse Laplace transforms 595


(a)L−^1


{
3
s^2 − 4 s+ 13

}
=L−^1

{
3
(s− 2 )^2 + 32

}

=e^2 tsin3t,
from (xii) of Table 63.1

(b)L−^1


{
2 (s+ 1 )
s^2 + 2 s+ 10

}
=L−^1

{
2 (s+ 1 )
(s+ 1 )^2 + 32

}

=2e−tcos3t,
from (xiii) of Table 63.1

Problem 6. Determine

(a)L−^1

{
5
s^2 + 2 s− 3

}

(b)L−^1

{
4 s− 3
s^2 − 4 s− 5

}

(a)L−^1


{
5
s^2 + 2 s− 3

}
=L−^1

{
5
(s+ 1 )^2 − 22

}

=L−^1


⎪⎨

⎪⎩

5
2

( 2 )
(s+ 1 )^2 − 22


⎪⎬

⎪⎭

=

5
2

e−tsinh2t,

from (xiv) of Table 63.1

(b) L−^1


{
4 s− 3
s^2 − 4 s− 5

}
=L−^1

{
4 s− 3
(s− 2 )^2 − 32

}

=L−^1

{
4 (s− 2 )+ 5
(s− 2 )^2 − 32

}

=L−^1

{
4 (s− 2 )
(s− 2 )^2 − 32

}

+L−^1

{
5
(s− 2 )^2 − 32

}

=4e^2 tcosh3t+L−^1


⎪⎨

⎪⎩

5
3

( 3 )

(s− 2 )^2 − 32


⎪⎬

⎪⎭

from (xv) of Table 63.1

=4e^2 tcosh 3t+

5
3

e^2 tsinh3t,

from (xiv) of Table 63.1

Now try the following exercise

Exercise 223 Further problemson inverse
Laplace transformsof simple functions
Determine the inverse Laplace transforms of the
following:


  1. (a)


7
s

(b)

2
s− 5

[(a) 7 (b) 2e^5 t]


  1. (a)


3
2 s+ 1

(b)

2 s
s^2 + 4
[
(a)

3
2

e−

1
2 t (b)2cos2t

]


  1. (a)


1
s^2 + 25

(b)

4
s^2 + 9
[
(a)

1
5

sin5t (b)

4
3

sin3t

]


  1. (a)


5 s
2 s^2 + 18

(b)

6
s^2
[
(a)

5
2

cos3t (b) 6 t

]


  1. (a)


5
s^3

(b)

8
s^4

[
(a)

5
2

t^2 (b)

4
3

t^3

]


  1. (a)


3 s
1
2

s^2 − 8

(b)

7
s^2 − 16
[
(a)6cosh4t (b)

7
4

sinh4t

]


  1. (a)


15
3 s^2 − 27

(b)

4
(s− 1 )^3
[
(a)

5
3

sinh3t (b)2ett^2

]


  1. (a)


1
(s+ 2 )^4

(b)

3
(s− 3 )^5
[
(a)

1
6

e−^2 tt^3 (b)

1
8

e^3 tt^4

]
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