PHYSICAL CHEMISTRY IN BRIEF

(Wang) #1
CHAP. 6: THERMODYNAMICS OF HOMOGENEOUS MIXTURES [CONTENTS] 160

Example
Calculate the fugacity coefficient and fugacity of carbon dioxide in an equimolar mixture with
hydrogen at temperature 30◦C and pressure 1 MPa given that the following equation of state
applies to this mixture
Vm=

RT

p

+B 11 x^21 +B 22 x^22 + 2B 12 x 1 x 2

wherex 1 is the mole fraction of carbon dioxide andx 2 is the mole fraction of hydrogen. The
second virial coefficients have the following values:B 11 =− 119 cm^3 mol−^1 , B 22 = 14cm^3 mol−^1
andB 12 =− 1 cm^3 mol−^1.

Solution
We calculate the fugacity coefficient using equation (6.85), and obtain the needed partial molar
volume of carbon dioxide from the equation of state and relation (6.52).

V 1 =

RT

p

+ (2B 12 −B 11 −B 22 )x^22 +B 11.

We integrate (6.85) to obtain

lnφ 1 =

∫p

0

[
Vi
RT


1

p

]
dp=

= [(2B 12 −B 11 −B 22 )x^22 +B 11 ]

p
RT

=

= [(− 2 ×1 + 119−14)× 0. 52 −119]×

1

8. 314 × 303. 15

=

= − 0. 026.

Henceφ 1 = 0. 974 , and for the fugacity of carbon dioxide we have

f 1 =φ 1 px 1 = 0. 974 × 1 × 0 .5 = 0. 487 MPa.
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