CHAP. 1: BASIC TERMS [CONTENTS] 37
Example
A binary mixture contains 4 moles of substance A and 6 moles of substance B. Express the
composition of the mixture using mole fraction and mole percent.
Solution
According to (1.6), the amount of substance in the mixture isn= 4+6 = 10 mol. From (1.5)
we getxA= 4/10 = 0.4,xB= 6/10 = 0.6. The mixture contains 40 mole percent of substance
A, and 60 mole percent of substance B.
A mixture in which mole fractions of all components have the same value is called an
equimolar mixture.
Example
Calculate the mole fractions of an equimolar mixture of hydrogen and oxygen, and the mole
fractions of an equimolar mixture of nitrogen, oxygen and argon.
Solution
It follows from the definition of an equimolar mixture that
xH 2 =xO 2 =
1
2
and
xN 2 =xO 2 =xAr=
1
3
1.6.2 Mass fractionwi
Definition
wi=
mi
m
, (1.8)
wheremiis the mass of componenti, andm=
∑k
i=1miis the mass of the mixture.
U Main unit:dimensionless quantity.