4.4. DUALITY AND DECOUPLING OF INTERACTION FIELDS 215
2.Electromagnetic force. If we consider the electromagnetic force, then the constant
β 6 =0 in (4.4.17). It is known that in the classical theory, the Coulomb potentialφsatisfies
the equation
(4.4.27) ∆φ=− 4 π ρ,
which is the stationary equation of (4.4.17) withμ=0 andΦe=0, and with the Coulomb
gauge in (4.4.23). For the case whereρ=eδ(r), the solution of (4.4.27) is the well-known
Coulomb potential:
(4.4.28) φ=
e
r
.
For the modified equations (4.4.17) and (4.4.18), the stationary time-componentequations
with the Coulomb gauge are given by
∆φ−
βe
̄hc
(4.4.29) φeφ= 4 πeδ(r)
(4.4.30) ∆φe= 0.
Only the radially symmetric solutions of (4.4.29) and (4.4.30) are physical. The radial solu-
tions of (4.4.30) are constants
φe=φ 0 the constants.
Thus the equations (4.4.29) and (4.4.30), in the spherical coordinate system, are reduced as
follows
(4.4.31)
1
r^2
d
dr
(r^2
d
dr
)φ−kφ=− 4 πeδ(r),
wherek=hc ̄eβ φ 0. The solutions of (4.4.31) are expressed as
(4.4.32) φ=
e
r
e−
√
kr.
The parameterkis to be determined by experiments.
We discuss the solutions (4.4.32) in the following three cases.
1) Case k= 0. The solution (4.4.32) in this case is reduced to the Coulomb potential
(4.4.28);
2) Case k> 0 .This solution is similar to the Yukawa potential for the strong interactions
of nucleons.
3) Case k< 0 .In this case, the solution can be written as
(4.4.33) φ=
e
r
cos
√
−kr+
αe
r
sin
√
−kr,
whereαis an arbitrary constant. The function
φ 0 =
1
r
sin
√
−kr
in (4.4.33) satisfies that
∆φ 0 −kφ 0 = 0.