7.1. ASTROPHYSICAL FLUID DYNAMICS 411
Then, in view of (7.1.28)-(7.1.31), the equation (7.1.76) can be expressed by
(7.1.79)
1
α
(
1
r^2
−
α′
rα
)
−
1
r^2
=−
8 πG
c^2
ρ 0 +
1
2 α ψ
ψ′φ′,
1
α
(
1
r^2
+
ψ′
rψ
)
−
1
r^2
=
8 πG
c^2
p+
1
α
φ′′−
1
2 α^2
α′φ′,
1
α
[
ψ′′
ψ
−
1
2
(
ψ′
ψ
) 2
−
α′ψ′
2 α ψ
+
1
r
(
ψ′
ψ
−
α′
α
)]
=
16 πG
c^2
p+
2
rα
φ′,
where the pressurepsatisfies the stationary equations of (7.1.78) withP=0 as follows
(7.1.80)
p′=−
c^2
2
ψ′ρ[ 1 −β(T−T 0 )],
κ
αr^2
d
dr
(
r^2
dT
dr
)
=−Q(r).
The functionsψandαsatisfy the boundary conditions (7.1.33), i.e.
(7.1.81) ψ(r 0 ) = 1 −
2 Gm
c^2 r 0
, α(r 0 ) =
(
1 −
2 Gm
c^2 r 0
)− 1
.
In addition, for the ordinary differential equations (7.1.79)-(7.1.81), we also need the bound-
ary conditions forψ′,φ′andT. Since−^12 c^2 ψ′represents the gravitational force, the condition
ofψ′atr=r 0 is given by
(7.1.82) ψ′(r 0 ) =
2 mG
c^2 r^20
.
Based on the Newton gravitational law,φ′is very small in the external sphere; also see
(Ma and Wang,2014e). Hence we can approximatively take that
(7.1.83) φ′(r 0 ) = 0.
Finally, it is rational to take the temperature gradient in the boundary condition as follows
(7.1.84)
∂T
∂r
(r 0 ) =−A (A> 0 ).
Let the stationary solution of the problem (7.1.79)-(7.1.81) be given by ̃p,T ̃,ψ,α,φ′.
Make the translation transformation
P→P, p→p+ ̃p, T→T+T ̃.
Then equations (7.1.78) are rewritten in the form
(7.1.85)
∂P
∂ τ
+
1
ρ
(P·∇)P=ν∆P−∇p+
c^2 ρ
2 α
dψ
dr
β~kT,
∂T
∂ τ
+
1
ρ
(P·∇)T=κ ̃∆T−
1
ρ
dT ̃
dr
Pr,
divP= 0 ,