Statistical Analysis for Education and Psychology Researchers

(Jeff_L) #1
which gives the value df=17.4

Interpretation

The t′-statistic represents the size of the difference between two groups, the larger the t′-
value the greater the size of the difference. In this example, the alternative hypothesis is
non-directional, H 1 :μ 1 ≠μ 2 , and the rejection region is |t|>t 1 −α/2. To be statistically
significant the calculated t′-value needs to exceed the critical t-value, with 17.4 degrees
of freedom at the 5 per cent level. Notice that the degrees of freedom is not a whole
number and a critical value for 17.4 df is not shown in the t-table in Appendix A4 (Table
3). We can find the critical value by interpolating between the two nearest values namely
df=17 (critical t=2.110) and df=18 (critical t=2.101). The critical value is approximately
2.106 with df=17.4. Using the TINV function in SAS the exact critical value is also
found to be 2.106. See the following SAS code,


data a;
alpha=0.975; ** This is equivalent to a two-tailed test
at the 5%
level**;
tcrit=round (tinv (0.975,17.4),.001); ** Round
statement rounds
value to**;
put tcrit=; ** 3 decimal
places ** ;
run;

In this example the observed t′-value of −3.0338 exceeds the critical t-value of 2.106, and
we can conclude that the means are significantly different at the 5 per cent level with a
two-tailed test. The 7-year-old pupils would seem to have a significantly higher score
than the 6-year-old pupils (t′=−3.0338, df=17.4, p<0.05).


Pooled Variance Estimate

Three steps are involved in calculating a pooled (equal variance) estimate: i) Check that
the sample variances are homogeneous and find the difference in means between the two
groups; ii) Calculate the standard error of the difference in means; and iii) evaluate t
which is the ratio of the difference in means (i above) to the standard error of this
difference in means (ii above).


1 Difference in means and check for homogeneity


The first step is the same as for the separate variance estimate, the
difference in means is −6.3. Using the approximate rule of thumb for
homogeneity of variances, (5.072/4.170 is less than 2) the variances are
similar.

2 Standard error of the difference in means (pooled variance estimate)


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