1—Basic Stuff 3
The other three functions are
sechx=
1
coshx
, cschx=
1
sinhx
, cothx=
1
tanhx
Drawing these is left to problem 4 , with a stopover in section1.8of this chapter.
Just as with the circular functions there are a bunch of identities relating these functions. For the analog
ofcos^2 θ+ sin^2 θ= 1you have
cosh^2 θ−sinh^2 θ= 1 (2)
For a proof, simply substitute the definitions ofcoshandsinhin terms of exponentials. Similarly the other
common trig identities have their counterpart here.
1 + tan^2 θ= sec^2 θ has the analog 1 −tanh^2 θ= sech^2 θ (3)
The reason for this close parallel lies in the complex plane, becausecos(ix) = coshxandsin(ix) =isinhx. See
chapter three.
The inverse hyperbolic functions are easier to evaluate than are the corresponding circular functions. I’ll
solve for the inverse hyperbolic sine as an example
y= sinhx means x= sinh−^1 y, y=
ex−e−x
2
Multiply by 2 exto get the quadratic equation
2 exy=e^2 x− 1 or
(
ex
) 2
− 2 y
(
ex