GTBL042-05 GTBL042-Callister-v3 September 28, 2007 21:43
2nd Revise Page
140 • Chapter 5 / Imperfections in Solids
Substitution of this expression and itsm′ 2 equivalent into Equation 5.16 gives
C 1 ′=
C 1 M′
100 A 1
C 1 M′
100 A 1
+
C 2 M′
100 A 2
× 100 (5.18)
Upon simplification we have
C 1 ′=
C 1 A 2
C 1 A 2 +C 2 A 1
× 100
which is identical to Equation 5.9a.
EXAMPLE PROBLEM 5.5
Composition Conversion—From Weight Percent to
Atom Percent
Determine the composition, in atom percent, of an alloy that consists of 97 wt%
aluminum and 3 wt% copper.
Solution
If we denote the respective weight percent compositions asCAl=97 and
CCu=3, substitution into Equations 5.9a and 5.9b yields
CAl′ =
CAlACu
CAlACu+CCuAAl
× 100
=
(97)(63.55 g/mol)
(97)(63.55 g/mol)+(3)(26.98 g/mol)
× 100
= 98 .7 at%
and
CCu′ =
CCuAAl
CCuAAl+CAlACu
× 100
=
(3)(26.98 g/mol)
(3)(26.98 g/mol)+(97)(63.55 g/mol)
× 100
= 1 .30 at%
Miscellaneous Imperfections
5.7 DISLOCATIONS—LINEAR DEFECTS
Adislocationis a linear or one-dimensional defect around which some of the atoms
VMSE
Edge
are misaligned. One type of dislocation is represented in Figure 5.8: an extra portion
of a plane of atoms, or half-plane, the edge of which terminates within the crystal.
This is termed anedge dislocation;it is a linear defect that centers around the line that
edge dislocation is defined along the end of the extra half-plane of atoms. This is sometimes termed