GTBL042-05 GTBL042-Callister-v3 September 28, 2007 21:43
2nd Revise Page140 • Chapter 5 / Imperfections in SolidsSubstitution of this expression and itsm′ 2 equivalent into Equation 5.16 givesC 1 ′=
C 1 M′
100 A 1
C 1 M′
100 A 1
+
C 2 M′
100 A 2
× 100 (5.18)
Upon simplification we haveC 1 ′=C 1 A 2
C 1 A 2 +C 2 A 1
× 100
which is identical to Equation 5.9a.EXAMPLE PROBLEM 5.5Composition Conversion—From Weight Percent to
Atom Percent
Determine the composition, in atom percent, of an alloy that consists of 97 wt%
aluminum and 3 wt% copper.Solution
If we denote the respective weight percent compositions asCAl=97 and
CCu=3, substitution into Equations 5.9a and 5.9b yieldsCAl′ =CAlACu
CAlACu+CCuAAl× 100
=
(97)(63.55 g/mol)
(97)(63.55 g/mol)+(3)(26.98 g/mol)× 100
= 98 .7 at%
andCCu′ =CCuAAl
CCuAAl+CAlACu× 100
=
(3)(26.98 g/mol)
(3)(26.98 g/mol)+(97)(63.55 g/mol)× 100
= 1 .30 at%Miscellaneous Imperfections
5.7 DISLOCATIONS—LINEAR DEFECTS
Adislocationis a linear or one-dimensional defect around which some of the atoms
VMSEEdgeare misaligned. One type of dislocation is represented in Figure 5.8: an extra portion
of a plane of atoms, or half-plane, the edge of which terminates within the crystal.
This is termed anedge dislocation;it is a linear defect that centers around the line that
edge dislocation is defined along the end of the extra half-plane of atoms. This is sometimes termed