GTBL042-03 GTBL042-Callister-v2 September 6, 2007 15:33
48 • Chapter 3 / Structures of Metals and Ceramics
Solution
For this coordination, the small cation is surrounded by three anions to form
an equilateral triangle as shown here, triangleABC; the centers of all four ions
are coplanar.
Cation
Anion
rA
rC
B
O
C
A
P
This boils down to a relatively simple plane trigonometry problem. Consid-
eration of the right triangleAPOmakes it clear that the side lengths are related
to the anion and cation radiirAandrCas
AP=rA
and
AO=rA+rC
Furthermore, the side length ratioAP/AOis a function of the angleαas
AP
AO
=cosα
The magnitude ofαis 30◦, since lineAObisects the 60◦angleBAC. Thus,
AP
AO
=
rA
rA+rC
=cos 30◦=
√
3
2
Solving for the cation–anion radius ratio, we have
rC
rA
=
1 −
√
3 / 2
√
3 / 2
= 0. 155
Table 3.4 Ionic Radii for Several Cations and
Anions (for a Coordination Number of 6)
Cation Ionic Radius (nm) Anion Ionic Radius (nm)
Al^3 + 0.053 Br− 0.196
Ba^2 + 0.136 Cl− 0.181
Ca^2 + 0.100 F− 0.133
Cs+ 0.170 I− 0.220
Fe^2 + 0.077 O^2 − 0.140
Fe^3 + 0.069 S^2 − 0.184
K+ 0.138
Mg^2 + 0.072
Mn^2 + 0.067
Na+ 0.102
Ni^2 + 0.069
Si^4 + 0.040
Ti^4 + 0.061