Answers to Odd-Numbered Problems 21
an “open strategy” is (.25)(1.5) (.25)(1.1) (.25)(.8) (.25)(.6)
$1.0 million. Thus, the “open” strategy is preferred.
b. The “open” strategy is less risky in the sense of having a narrower
range of possible outcomes. Managerial risk aversion would be an
added reason to pursue this strategy.
- a. The tree lists the six possible outcomes (in thousands of dollars) and
the expected value of each chance circle. Overall expected profit is
$1,500.
1.5
.2
.5
R = 120
.3
R = 160
R = 175
.6
C = 150
.4
C = 170
.6
C = 150
.4
C = 170
.6
C = 150
.4
C = 170
–30
–50
10
–10
25
5
–38
2
17
b. E (revenue) (.2)(120,000) (.3)(160,000) (.5)(175,000)
$159,500. Expected cost is: (.6)(150,000) (.4)(170,000) $158,000.
Thus, the expected profit is $159,500 $158,000 $1,500, the same
result as in part (a).
- a. Let’s compute the expected costs (in $ billions) of the respective
safety programs. For the “standard” program, the expected cost is:
.160 (.01)(10) $.26 billion. For the “lax” program, the expected
cost is: .040 (.03)(10) $.34 billion. For the “ultraconservative”
program, the expected cost is: .240 (.005)(10) $.29 billion. A
risk-neutral BP would choose the standard program because it delivers
the lowest expected cost.
b. At a judged 2 percent disaster risk, the (apparent) expected cost of
the “lax” policy is: .040 (.02)(10) $.24 billion, making it appear to
be the least-cost option. A judged $5 billion liability would reduce the
expected cost for all three options. The biggest apparent reduction
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