contribution of ($2)(2) ($1)(1) $5. The contribution of process
2 is ($2)(2) ($1)(4) $8 at the unit level. Thus, the LP
formulation is
Maximize:
Subject to:
In the graphic solution, both constraints are binding. The optimal
solution is x 1 50 and x 2 30. Total contribution is $490.
b. Let the supply of labor increase to 120. The new solution is x 1 40
and x 2 40, and total contribution increases to $520. Labor’s shadow
price is 30/10 $3.
c. If the contribution of plywood rises to $3, the new objective function
becomes maximize 7x 1 16x 2. The slope of the objective function
(7/16) no longer lies between the slopes of the input constraints
(1/2 and 1). Therefore, only the labor constraint is binding, and
the firm only uses the second process (i.e., x 1 0). Solving the
binding labor constraint, we have x 2 55. The firm’s maximum
contribution is (16)(55) $880.
- a. The LP formulation is
Minimize:
Subject to:
,
where L, M, and D (are all nonnegative integers) and denote the
number of roundtrips to Los Angeles, Miami, and Durham, respectively.
Using a spreadsheet optimizer, one finds the solution, L 3, M 1,
and D 2. The total cost of these six round trips (comprising 20,568
total miles and 12 segments) is $1,975.
b. If the challenge is to fly 25,000 miles, the best solution is: L 4, M2,
and D 0. The total cost of these trips (covering 25,840 miles)
increases to $2,300. Finally, if the requirement is 20,000 miles and
only 10 segments, the optimal solution is: L 3, M2, and D 0
(20,640 miles flown) at a cost of $1,875.
5,200L2,520M1,224D20,000
2L2M2D 12
425L300M200D
2x 1 2x 2 160.
x 1 2x 2 110
5x 1 8x 2
36 Answers to Odd-Numbered Problems
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