501 Geometry Questions

(Jacob Rumans) #1

Set 57



  1. P= 6x+ 4y. Add all of the sides together and combine like terms:
    P= 6x+ 4y; y+ x+ (3y– 2) + (x+ 3) + (2x– 1) + 2x= 6x+ 4y

  2. p= 50. Using your knowledge of rectangles and their congruent
    sides, you find the measure of each exterior side not given. To find
    the perimeter, you add the measure of each exterior side together.
    1 + 6 + 1 + 6 + 1 + 4 + 1 + 4 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 3 + 3 + 5


+ 5 = 50.


  1. p= 34 + 4 5 .First, find the hypotenuse of at least one of the two
    congruent triangles using the Pythagorean theorem: 2^2 + 4^2 = c^2.
    42 + 16^2 = c^2. 20 = c^2. 2 5 = c. Add the measure of each exterior
    side together: 2 + 5 + 2 + 2 + 2 + 2 +2 + 5 + 2 + 2 5 + 4 + 2 + 4 +
    2  5 = 34 + 4 5 .

  2. p= 32 + 2 5 .First find the hypotenuse of at least one of the two
    congruent triangles using the Pythagorean theorem: 1^2 + 2^2 = c^2.
    1 + 4 = c^2.  5 = c. Add the measure of each exterior side together.
    2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 +  5 +
     5 = 32 + 2 5 .


Set 58



  1. y= 4 13 .CGand BHare congruent because the opposite sides
    of a rectangle are congruent. Plug the measurements of ΔABH
    into the Pythagorean theorem: 12^2 + 8^2 = y^2. 144 + 64 = y^2.
    208 = y^2. 4 13 = y.

  2. p= 48 + 8 13 .Figure ABDE is an isosceles trapezoid; ABis
    congruent to ED. Add the measurements of each exterior line
    segment together: 6 + 6 + 4 13 + 12 + 6 + 6 + 12 + 4 13 =
    48 + 8 13 .


501 Geometry Questions
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