- 10.5 feet^2 .Find the area of a rectangle with sides 6 feet and 3 feet:
A= 6 ft. ×3 ft. = 18 sq. ft. Find the area of both triangular voids:
Area of the smaller triangular void = ^12 (3 ft. ×1 ft.) = 1.5 sq. ft. Area
of the larger triangular void = ^12 (6 ft. ×2 ft.) = 6 sq. ft. So, the total
area of the triangular voids is 1.5 ft. + 6 ft. = 7.5 sq. ft. Subtract 7.5
sq. ft. from 18 sq. ft. (the area of the full rectangle) and 10.5 square
feet remain.
Set 65
- 480 feet^2 .You can either treat figure ABCD like a trapezoid or
like a parallelogram and a triangle. However you choose to work
with the figure, you must begin by finding the measurement of ED
using the Pythagorean theorem: a^2 + 16^2 = 20. a^2 +256 = 400.
a^2 = 144. a= 12. Subtract 12 feet from 36 feet to find the
measurement of BC: 36 – 12 = 24 feet. Should you choose to treat
the figure like the sum of two polygons, find the area of each
polygon separately and add them together. Area of parallelogram
ABCE: 16 ft. ×24 ft. = Total area of the quadrilateral: 384 sq. ft.
Area of ΔECD: ^12 ×16 ft. ×12 ft. = 96 sq. ft. Total area of the
quadrilateral: 384 sq. ft. + 96 sq. ft. = 480 sq. ft. Should you choose
to treat the figure like a trapezoid and need to find the area, simply
plug in the appropriate measurements: ^12 ×16 ft. (24 ft. + 36 ft.) =
480 feet^2. - 60 + 2 5 feet^2 .Extend TWto RV. Let’s call this XW. XW
perpendicularly bisects RV; as a perpendicular bisector, it divides
isosceles triangle RWV into two congruent right triangles and
establishes the height for parallelograms RSTW and VUTW.
Solve the area of parallelogram VUTW: 2 ft. ×15 ft. = 30 sq. ft.
Find the height of ΔRWV using the Pythagorean theorem: a^2 + 2^2
= 3^2. a^2 + 4 = 9. a^2 = 5. a= 5 . Solve the area of ΔRWV: ^12 × 5
ft. ×4 ft. = 2 5 sq. ft. Add all the areas together: 2 5 sq. ft. + 30
sq. ft. + 30 sq. ft. = 60 + 2 5 feet^2. - 24.0 feet^2 .Rhombuses KLQR and MNOP are congruent. Their
areas each equal 2.5 ft. ×3 ft. = 7.5 sq. ft. The area of square
LMPQ equals the product of two sides: 3 ft. ×3 ft. = 9 ft. The sum
of all the areas equal 9 sq. ft. + 7.5 sq. ft. + 7.5 sq. ft. = 24 feet^2.
501 Geometry Questions