501 Geometry Questions

(Jacob Rumans) #1

Answers


Set 81



  1. x= 6 feet.The radius of cylinder P is represented by x; it is the
    only missing variable in the volume formula. Plug it in and solve
    for x: 432πcubic ft. = (πx^2 )12 ft. 36 sq. ft. = x^2. 6 feet = x.

  2. Surface area= 216πsquare feet.The surface area of a cylinder is
    2 πr^2 + 2πrh: Plug the variables in and solve: SA = 2π(6 ft)^2 + 2π(6
    ft. ×12 ft.). 72πsq. ft.+ 144πsq. ft. = 216πsq. ft.

  3. Total volume= 864πcubic feet.This problem is easier than
    you think. Each cone has exactly the same volume. The three
    cones together equal the volume of the cylinder because a cone
    has ^13  the volume of a cylinder with the same height and radius.
    Multiply the volume of the cylinder by 2, and you have the
    combined volume of all three cones and the cylinder.


Set 82



  1. x= ^12 inch. The formula for volume of a sphere is πr^3. In this
    question xis the value of r. Plug the variables in and solve for x:
    ^16 π= πx^3. ^16 = x^3. ^12 = x.

  2. y= ^14 inch.The volume of a cone is ^13 πr^2 h, where yis the value of
    r. Plug in the variables and solve:  916 πcubic in. = ^13 πy^2 ^12 in.  916 π
    cubic in. = ^16 πy^2.  116 πsq. in. = y^2. ^14 inch = y.

  3. Surface area= 1.0πsquare inch.The candy inside the wrapper is
    a perfect sphere. The formula for its surface area is 4πr^2. Plug the
    variables in and solve: SA = 4π(0.5 inch)^2. SA= 1.0πsquare inch.


Set 83



  1. Jarret.The volume of a half sphere is ^12 (^43 πr^3 ). Tracy’s half scoop is
    then ^12 (^43 π×1 inch^3 ), or ^23 πcubic inches. The volume of a cone is
    ^13 πr^2 h. The ice cream in the cone is ^13 π(1 inch^2 ×3 inches), or π
    cubic inches. Jarret has ^13 πcubic inches more ice cream than Tracy.


501 Geometry Questions
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