- Approximately 235.9 cubic meters.Joe removed the same
amount of material as volume in the sphere, or ^43 π(1.5 meters)^3 ,
which simplifies to 4.5πcubic meters. The remaining volume is
250 cubic meters – 4.5πcubic meters, or approximately 235.9
cubic meters. - 1,518 candies.The volume of each piece of candy is ^43 π(0.25 inches)^3 ,
or 0.02πcubic inches. The volume of the jar is π(2.25 inches^2 ×6)
inches, or 30.375πcubic inches. Divide the volume of the jar by
the volume of a candy , and 1,518 candies can theoretically
fit into the given jar (not including the space between candies). - Remaining volume≈57.6 ft.First, find the volume of the cube,
which is (4.5 feet)^3 , or approximately 91.1 cubic feet. The volume
of the sphere within is only ^43 π(2 feet)^3 , or approximately 33.5
cubic feet. Subtract the volume of the sphere from the volume of
the cube. The remaining volume is approximately 57.6 cubic feet.
Set 85
- V= 18πcubic inches. Volume of a cone = ^13 πr^2 h.
V= ^13 π(3 in.)^2 (6 in.). - V= 36πcubic inches.Volume of a sphere = ^43 πr^3. V= ^43 π(3 in.)^3.
- 16 πcubic inches. Volume of a cylinder = πr^2 h. V= π(1 in.^2 ×4 in.)
V= 4πcubic inches. There are four arm segments, so four times
the volume = 16πcubic inches. - ^83 πcubic inches. Volume of a sphere = ^43 πr^3. V= ^43 π(1 in.^3 ). V= ^43 π
cubic inches. There are two handballs, so two times the volume =
^83 πcubic inches. - 90 πcubic inches. The body is the sum of two congruent half
spheres, which is really one sphere, and a cylinder. Volume of a
sphere= ^43 πr^3. V= ^43 π(3 in.)^3. V= 36πcubic inches. Volume of a
cylinder= πr^2 h. V= π(3 in.)^2 (6 in.);V= 54πcubic inches. Total
volume= 90πcubic inches.
30.375πcubic inches
0.02πcubic inches501 Geometry Questions