Answers
Set 94
- d.The xand yvariables in linear equations can only have exponents
of 1. If xor yis squared or cubed, then it is not a linear equation. - a.Change –2x+ 3y= –3 into slope-intercept form by adding 2xto
both sides and dividing everything by 3. The slope-intercept form
is y= ^23 (x) – 1, where the slope = ^23 and the y-intercept = –1. - d.Plug the value of xand yfrom the given coordinate pair into the
equation and solve: 3 = ^12 (–2) + b. 3 = (–1) + b. 4 = b. - c.The only point that does not satisfy the linear equation
(^32 )x– 2y= 14 is (–2,^127 ) : ^32 (–2) – 2(^127 ) = –3 – 17 = –20. –20 ≠14. - a.To convert a standard linear equation into a slope- intercept
equation, single out the yvariable. Subtract 4xfrom both sides:
–2y= –4x+ 4. Divide both sides by –2: y= 2x– 2. Choices cand d
are incorrect because they single out the xvariable. Choice bis
incorrect because after both sides of the equation are divided by
–2, the signs were not reversed on the right hand side. - c.Find the slope between any two of the given points: (–(0 4 – –^30 ))= ––3 4 ,
or ^34 . •B is the y-intercept. Plug the slope and yvalue of •B into the
formula y= mx+ b. y= ^34 x+ 3. - d.The unknown yvalue is also the intercept value of a line that
connects all three points. First, find the slope between •A and •C:
–3 – 3 = –6. –1 – (–9) = 8. –^86 or – 34 represents the slope. From •A,
count right three spaces and down four spaces. You are at point
(0,–5). From this point, count right three spaces and down four
spaces. You are at point (3,–9). Point (0,–5) is on the line connecting
- A and •C; –5 is your unknown value for y.501 Geometry Questions