501 Geometry Questions

(Jacob Rumans) #1

  1. Side-Angle-Side:
    Set one: BCEF, ∠BCA ∠EFG, CAFG
    Set two: BCEFHI
    ∠BCD ∠EFD ∠I
    CDFDIG

  2. BCEFHI2 and also DCDFGI2.Therefore
    ΔBCD and ΔEFD are right isosceles triangles with two base angles
    that each measure 45° and congruent hypotenuses. Since BD
    ED, DADG, and∠BDA∠EDG,ΔABDΔGED by the
    side-angle-side postulate.


Set 31



  1. ΔKML and ΔGIJ. (Remember to align corresponding
    vertices.)

  2. KMGI
    MLIJ
    LKJG
    (Always coordinate corresponding endpoints.)

  3. Side-Side-Side: KMGI
    MLIJ
    LKJG

  4. m∠∠V = 43°.ΔIMK is an isosceles triangle. Its vertex angle
    measures 26°; its base angles measure 77° each. 180° – (m∠IKM +
    m∠MKL) = m∠JKL. 180° – (77° + 60°) = m∠JKL. m∠JKL = 43°.


Set 32



  1. ΔKBO and ΔHGO are congruent; Side-Angle-Side postulate.

  2. Isosceles right triangle.

  3. 90°. ΔBOK and ΔGOK are isosceles right triangles, ∠BOK
    ∠GOH = 45°, so ∠KOH must be 90°.


501 Geometry Questions
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