- Side-Angle-Side:
Set one: BCEF, ∠BCA ∠EFG, CAFG
Set two: BCEFHI
∠BCD ∠EFD ∠I
CDFDIG - BCEFHI2 and also DCDFGI2.Therefore
ΔBCD and ΔEFD are right isosceles triangles with two base angles
that each measure 45° and congruent hypotenuses. Since BD
ED, DADG, and∠BDA∠EDG,ΔABDΔGED by the
side-angle-side postulate.
Set 31
- ΔKML and ΔGIJ. (Remember to align corresponding
vertices.) - KMGI
MLIJ
LKJG
(Always coordinate corresponding endpoints.) - Side-Side-Side: KMGI
MLIJ
LKJG - m∠∠V = 43°.ΔIMK is an isosceles triangle. Its vertex angle
measures 26°; its base angles measure 77° each. 180° – (m∠IKM +
m∠MKL) = m∠JKL. 180° – (77° + 60°) = m∠JKL. m∠JKL = 43°.
Set 32
- ΔKBO and ΔHGO are congruent; Side-Angle-Side postulate.
- Isosceles right triangle.
- 90°. ΔBOK and ΔGOK are isosceles right triangles, ∠BOK
∠GOH = 45°, so ∠KOH must be 90°.
501 Geometry Questions