272 PART 2 QUANTUM MECHANICS AND SPECTROSCOPY
Operators (Table 9.1)
r→r
To solve this equation, we make some assumptions. The interactions
between the two electrons, and the two nuclei, are assumed to be neg-
ligible compared to the interactions between the nuclei and electrons: this
eliminates two of the six terms for the potential. With these assumptions,
Schrödinger’s equation for the hydrogen molecule can be written as:
(13.4)
The wavefunction describing the two electrons is simplified as the product
of wavefunctions for each electron ψ(r 1 ,r 2 ) =ψ(r 1 )ψ(r 2 ): the validity of
this assumption will be addressed later. The equation can be rewritten
by realizing that the derivative operators are specific to either electron 1
or 2, and so for each derivative operator part of the wavefunction can
be considered to be a constant, yielding:
=Eψ(r 1 ,r 2 ) (13.5)
This expression can be simplified by dividing the entire equation by
ψ(r 1 )ψ(r 2 ) and grouping together the terms that depend upon r 1 and r 2 :
(13.6)
These two equations can be separated by setting each of the individual
parts equal to E 1 and E 2 , which together add up to E. In this case, the asso-
ciation of the wavefunctions to the nuclei A and B are shown explicitly
by the subscript.
−∇−−
()
()
Z^2
2
2
2
2
2
02
2
(^20)
1
4
1
4
1
mr
r
e
r
e
ψ
ψ
πε A πε rr
E
B2
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
=
−∇−−
Z^2
1
1
2
1
2
01
2
(^20)
1
4
1
4
1
mr
r
e
r
e
ψ r
ψ
() πε πε
()
A BB1
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
−∇+∇−
Z^2
21
2
112
2
2
2
24 m 0
rrrr
e
[()()()()]ψψψψ
πε
11111
rrrrrr^12
A1 A2 B1 B2
+++ (, )
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
ψ
−∇+∇ − +
Z^2
1
2
2
2
12
2
(^240)
11
m
rr
e
rr
()(,)ψ
πε A1 A 2 2B1B2
++ (, ) (,
⎡
⎣
⎢
⎢
⎤
⎦
⎥
⎥
=
11
rrψψrr^12 E rr^12 ))
p
i