BioPHYSICAL chemistry

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272 PART 2 QUANTUM MECHANICS AND SPECTROSCOPY


Operators (Table 9.1)

r→r

To solve this equation, we make some assumptions. The interactions
between the two electrons, and the two nuclei, are assumed to be neg-
ligible compared to the interactions between the nuclei and electrons: this
eliminates two of the six terms for the potential. With these assumptions,
Schrödinger’s equation for the hydrogen molecule can be written as:

(13.4)

The wavefunction describing the two electrons is simplified as the product
of wavefunctions for each electron ψ(r 1 ,r 2 ) =ψ(r 1 )ψ(r 2 ): the validity of
this assumption will be addressed later. The equation can be rewritten
by realizing that the derivative operators are specific to either electron 1
or 2, and so for each derivative operator part of the wavefunction can
be considered to be a constant, yielding:

=Eψ(r 1 ,r 2 ) (13.5)

This expression can be simplified by dividing the entire equation by
ψ(r 1 )ψ(r 2 ) and grouping together the terms that depend upon r 1 and r 2 :

(13.6)

These two equations can be separated by setting each of the individual
parts equal to E 1 and E 2 , which together add up to E. In this case, the asso-
ciation of the wavefunctions to the nuclei A and B are shown explicitly
by the subscript.

−∇−−

()

()

Z^2

2

2

2
2

2

02

2

(^20)


1

4

1

4

1

mr

r

e
r

e
ψ

ψ
πε A πε rr

E

B2









=

−∇−−

Z^2

1

1
2
1

2

01

2

(^20)


1

4

1

4

1

mr

r
e
r

e
ψ r

ψ
() πε πε

()

A BB1









−∇+∇−

Z^2

21
2
112
2
2

2
24 m 0

rrrr
e
[()()()()]ψψψψ
πε

11111

rrrrrr^12
A1 A2 B1 B2

+++ (, )









ψ

−∇+∇ − +

Z^2

1
2
2
2
12

2

(^240)


11

m

rr
e
rr

()(,)ψ
πε A1 A 2 2B1B2

++ (, ) (,









=

11

rrψψrr^12 E rr^12 ))

p
i

→∇

Z
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