7.6 They are both equal to 0.05 M.
7.7 [B]/[C] =10 and [B] +[C] =0.1 M
10[C] +[C] =11[C] =0.1 M →[C] =0.009 M and [B] =0.09
7.8 (a)
(b) =−(2.0 M−^1 s−^1 )(0.1 M)(0.1 M) =−0.02 Ms−^1
=−(2.0 M−^1 s−^1 )(0.1 M)(0.1 M) =−0.02 Ms−^1
=(2.0 M−^1 s−^1 )(0.1 M)(0.1 M) −(1.0 s−^1 )(0.1 M)
+(5.0 s−^1 )(0.1 M) =0.42 Ms−^1
=(1.0 s−^1 )(0.1 M) −(5.0 s−^1 )(0.1 M) =−0.40 Ms−^1
(c) At equilibrium the concentrations of A and B are zero since the
reactions are irreversible. The sum of the concentrations must
be equal to 0.4 M and the ratio of the amounts of C and D is
given by the ratio of the two rate constants:
[C] +[D] =[C] +0.2[C] =0.4 M →[C] =1/3 M
[D] =0.2[C] =1/15 M
7.9
7.10 (a)
(b)
(c) Since the reaction is irreversible, the final concentration of A is
zero and that of B is 0.2 M.
dB
d
As M Ms
[]
[] ( )(. ).
t
=+kf =101 01−−^11 =
dA
d
AsM Ms
[]
[] ( )(. ).
t
=−kf =− 101 −−^11 =− 01
dA
d
A
dB
d
A
[]
[]
[]
[]
t
k
t
=−ff=+k
AAekt. ek s k
() ln.
=→= 0 −− 05 10 =−
05
10
Mor
s
=0 0693. s−^1
K
k
k
f
b
[]
[]
===→=.[].[]
D
C
(^2) D C and
2
02 02 [[] [ ] .CD+= 04 M
dD
d
[]
t
dC
d
[]
t
dB
d
[]
t
dA
d
[]
t
dC
d
AB C D
dD
d
[]
[][] [] []
[]
t
kkk
ffbt
=−+ 122 ==−kkfb 22 []CD[ ]
dA
d
AB
dB
d
AB
[]
[][]
[]
[][]
t
k
t
=−ff 11 =−k
450 ANSWERS TO PROBLEMS
9781405124362_5_end.qxd 4/29/08 9:17 Page 450