BioPHYSICAL chemistry

(singke) #1
12.19 A wavefunction can have a node where the value is exactly equal
to zero. For the 2s orbital this occurs at:

12.20Φ(φ+ 2 π) =Φ(φ)
Aeimlφ=Aeiml(φ+^2 π)=Aeimlφeiml^2 π
1 =eiml^2 π=cos(2πml) +isin(2πml)
with ml=0, ±1, ±2, ±3,....

12.21

12.22

−Bsinθ(2sinθcosθ) + 2 Bcosθsin^2 θ= 0
0 = 0

12.23

The second term is zero since:

This leaves the first term and:

E

me
=−

4
2
0
32 πεZ^2

α
πε

=

me
Z^2

2

(^40)
re
mE
e
−−rre








⎜⎜



αααα⎟⎟+−+
πε

2
2

2

0

2

2

4

2

Z

mm
Z^2

0



⎜⎜



⎟⎟=

αα
πε

2 αα
2

2

0

2

2

4

re e

me
r

−−rr−+ +Er



⎜⎜



⎟⎟

Z

ee−αr= 0

d
d

2
2

2
r

Π()rreee=− −αα( −−ααrr+ )−α−αr=αrre−−ααrr− 2 αe

d
dr

Π()rr e e=−( )α −−ααrr+

−+=BBsinθ [sin ] cos sin
θ

θθθ
d
d

(^2220)
sinθ [sin ( sin )] cos sin
θ
θθ θθ
d
d


−+BB 202 =

sinθ sin ( cos ) [ ( )
θ

θ
θ

θ
d
d

d
d

B









++11 1 ssin^2 θθ−= 00 ]( cos )B

d
d

d
d

2
2

2
φ

φ
φ

Φ()==( ( )Aim e φφ) Aim e( )
l

im
l
llim =−m ()
l

(^2) Φφ
d
d
d
φ d
φ
φ
Φ()==(Aeimφφ) A im e( )
l
llim
ψ
π
ρ ρ
200
3
0
3
(^14)
224


2

2

=−/ 0



⎜⎜



⎟⎟ − =

Z

a

e wheenρ= 4

ANSWERS TO PROBLEMS 469


9781405124362_5_end.qxd 4/29/08 9:17 Page 469

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