CHAPTER 14
14.1 A=εcl
where the proportionality constant εis the molar absorption co-
efficient, or extinction coefficient, the concentration of the absorber
is c, the pathlength of the sample is l, the intensity of the incident
light is I, and the intensity of the exiting light is I 0.
14.2 (a)
(b)
(c)
14.3 (a)
(b)
(c)
14.4 (a)A=0.27
(b)
14.5 (a)A=0.0154
(b)
14.6
14.7 (a)A=cεl=(1 × 10 −^6 M)(1 × 104 M−^1 cm−^1 )(1 cm) =0.01
(b)A=cεl=(2 × 10 −^4 M)(1 × 104 M−^1 cm−^1 )(1 cm) = 2
14.8
14.9 w′=B′ρ
[]
(, )(. ) ( )(.
Trp =
11 300MM−−^11 0 239 − 1500 0 71 77
11 300 5380 1500 1960
112
)
( , )( ) ( )( )
.
MM−−−
= 8 81 10× −^5 M
[]
()(.)()(.)
Tyr =
5380 MM−−^11 0 717 − 1960 0 239
(( , )( ) ( )( )
.
11 300 5380 1500 1960
11585
MM−−−
=× 10 −^5 M
c
A
l
==.
×
=
−
ε −−
10
10 1
01
1
31 1Mcm cm mM
c
A
l (. )( )
==.
×
=
−
ε −−
10
154 10 1
6
1
41 1Mcm cm^551065
×=−^6 MM. μ
c
.
=× =.%. %
1
27
01 0037
λ
ν
==
×
×
=×
−
−
c (^310) −
110
310
81
12 1
ms 4
s
m→infrared
λ
ν
==
×
×
=× →
−
−
c 310
110
310
81
61
ms 2
s
mrradiowave
λ
ν
==
×
×
=×
−
−
c (^310) −
110
310
81
18 1
ms 10
s
mm→X-ray
ν
λ
==.
×
×
=×
−
−
c 310
310
10 10
81
2
ms 10
m
m→microwave
ν
λ
==.
×
×
=×
−
−
c 310
510
60 10
81
7
ms 14
m
m→→visible
ν
λ
==
×
×
=× →
−
−
c 310
110
310
81
9
ms 17
m
m X-ray
ANSWERS TO PROBLEMS 473
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