CHAPTER 3 SECOND LAW OF THERMODYNAMICS 65
Since each term has a logarithm, this equation reduces to:
or (db3.11)
Tfinalc Vinitial=Tinitialc Vfinal
If lnx=lnythen ln(x/y) =1 and x=y
For the Carnot cycle, the products are:
VAThotc =VDTcoldc and VCTcoldc =VBThotc (db3.12)
Dividing these two expressions gives:
VAThotc =VDTcoldc and VCTcoldc =VBThotc
(db3.13)
Consequently, we can substitute these volume ratios into the expression for the heat flow
(eqn db3.4):
(db3.14)
VT
VT
VT
VT
Ahot
c
Bhot
c
Dcold
c
Ccold
= c or
VV
V
V
V
A
B
D
C
=
T
T
V
V
nal
initial
c
nal
initial
⎛ 33
⎝
⎜⎜
⎞
⎠
⎟⎟ =
⎛
⎝
⎜⎜
⎞
⎠⎠
⎟⎟
and
or
q
T
q
T
hot
hot
cold
cold
−= 0
q
q
nRT
V
V
nRT
V
V
hot T
cold
hot
b
a
cold
b
a
ln
ln
=
−
=−hhot
Tcold
qnRT
V
V
nRT
V
V
cold cold d nR
c
cold
a
b
==ln ln =− TT
V
cold V
b
a
ln
qnRT
V
hot hot V
b
a
= ln