Computer Aided Engineering Design

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DIFFERENTIAL GEOMETRY OF SURFACES 187

nu · rv = a 1 ru·rv + b 1 rv·rv⇒–M = a 1 G 12 + b 1 G 22 ⇒b 1 = 0 (QM = 0, G 12 = 0)

Therefore, nruu
L
G
=–
11
(6.47)


Similarly,
nv = a 2 ru + b 2 rv⇒nv · ru = a 2 ru·ru + b 1 rv·ru⇒–M = a 2 G 11 + b 2 G 12
⇒a 2 = 0 (QG 12 = 0, M = 0)


nv · rv = a 2 ru·rv + b 2 rv·rv⇒–N = b 2 G 22 ⇒b 2 = – N
G 22
(Qa 2 = 0)

Therefore, nrvv=–


N
G 22 (6.48)
Using these expressions for nu and nv,K and H can be determined as follows:


rruuaGL ru rr ru r r

aL
G a

N
G

aN
G

*
11 11

*
22 22

= – = 1 – ⎛ , = – = 1 –






vvvv⎠ (6.49a)

G
aL
G

aL
G
11 ***uu uu G
11

2

11

2
= rr⋅ = 1 – rr = 1 – 11




⋅ ⎛


⎠ (6.49b)

G

aL
G

aN
G

aL
G

aN
G
12 ***uuG
11 22 11 22

= = 1 – 1 – = 1 – 1 – = 0rr⋅ rr 12








⋅ ⎛






vv⎠ (6.49c)

G
aN
G

aN
G
22 *** G
22

2

22

2
= = 1 – rrvvvv⋅ = 1 –rr 22




⋅ ⎛


⎠ (6.49d)

L

aL
G L

aL
G M

aL

= –uu = – 1 – (^) uu = 1 – , = – u = – 1 – G u = 0

11 11

11
r n⋅ ⎛ rn r r rn



⋅ ⎛



⋅ ⎛



vv⋅
(6.49e)
N
aN
G
aN
G
*= – * = – 1 – = 1 – N
22 22
rnvvvv⋅ ⎛ rn



⋅ ⎛


⎠ (6.49f)
The principal curvatures at point P
on S can now be determined as follows:
κκ 1

11



  • 11
    11
    2


  • 22




  • 22
    22
    = =
    1–
    , = =
    1–
    L
    G
    L
    aL
    G G
    N

    G
    N
    aN
    G G








    (6.50)
    The Gaussian and mean curvatures of S* are given by
    K NL
    GG
    aL
    G
    aN
    G
    K
    a L
    G
    N
    G
    a NL
    GG
    K
    aH a K




  • = =
    1– 1–


    1 – + +


    1– 2 +
    2




  • 2




  • 22 11
    11 22
    11 22
    2
    11 22
    2
    κκ












    (6.51)
    H
    L
    G
    aL
    G
    N
    G
    aN
    G
    HKa
    aH a K



  • =^1
    2
    ( + ) =^1
    2 1–



  • 1–
    = +
    1– 2 +
    1 2
    11 11 22 22 2
    κκ ⎛














    ⎟ (6.52)

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