328 COMPUTER AIDED ENGINEERING DESIGN
whereB is the strain-displacement matrix which is a constant and depends on the position of nodal
coordinates. Thus, a triangular element is sometimes referred to as the constant strain triangular or
CST element. From linear elasticity, strains are related to stresses in three dimensions as
εσνσσxxyz
E
=^1 [] – ( + )
εσνσσyyzx
E
=^1 [] – ( + ) (11.10j)
εσνσσzzxy
E
=^1 [] – ( + )
γ
τ
γ
τ
γ
τ
xy
xy
yz
yz
xz
xz
= GGG, = , =
whereE is the elastic modulus, ν is the Poisson’s ratio and G is the shear modulus defined as
G = E
2 (1 + )ν
. Also σx,σy and σz are the normal stresses along the subscript directions and τxy is the
shear stress in the x plane along the y direction. For a plane stress case, where the stresses are non-
zero only in a plane, say, the xy plane (that is, σz = τxz = τyz = 0), we have
εσνσ σ
νν
ε
νν
ε
εσνσ σ
νν
xxy x x y
yyx y
E
E
E
E
=^1 [ – ()] =
2
1
1 –
+
1
1 +
+^1
1 –
1
1 +
=^1 [ – ()]or =
2
1
1 –
1
1 +
⎛
⎝
⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
⎟
⎡
⎣
⎢
⎤
⎦
⎥
⎛
⎝
⎜⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
⎟
⎡
⎣
⎢
⎤
⎦
ε ννε ⎥
γ
ντ
τ
γ
ν
xy
xy
xy
xy
xy
E
E
+^1
1 –
+
1
1 +
=
2 (1 + )
=
2 (1 + )
(11.10k)
which in matrix form becomes
= =
(1 – )
10
10
00 1 –
2
=
σ
σ
τ
ν
ν
ν
ν
ε
ε
γ
x
y
xy
x
y
xy
E
⎛
⎝
⎜
⎜
⎜
⎞
⎠
⎟
⎟
⎟
⎛
⎝
⎜
⎜
⎜⎜
⎞
⎠
⎟
⎟
⎟⎟
⎛
⎝
⎜
⎜
⎜
⎞
⎠
⎟
⎟
⎟
2 D (11.10l)
whereD is the elasticity matrix for the plane stress case. The strain energy stored in the element then
is
SE dV d V dV dV
V
T
V
T
V
TT T
V
=^1 T
2
=^1
2
=^1
2
=^1
∫∫ ∫ 2 ∫
⎧
⎨
⎩
⎫
⎬
⎭
D u B DBu u B DB u
The element stiffness matrix ke is
ke B DB B DB
V
= TTdV At=
∫
(11.10m)
wheret is the out-of-plane thickness and the constant matrices B and D are given by Eqs. (11.10i) and
(11.10l).