328 COMPUTER AIDED ENGINEERING DESIGN
whereB is the strain-displacement matrix which is a constant and depends on the position of nodal
coordinates. Thus, a triangular element is sometimes referred to as the constant strain triangular or
CST element. From linear elasticity, strains are related to stresses in three dimensions as
εσνσσxxyz
E
=^1 [] – ( + )εσνσσyyzx
E
=^1 [] – ( + ) (11.10j)εσνσσzzxy
E
=^1 [] – ( + )γτ
γτ
γτ
xyxy
yzyz
xz
xz
= GGG, = , =whereE is the elastic modulus, ν is the Poisson’s ratio and G is the shear modulus defined as
G = E
2 (1 + )ν. Also σx,σy and σz are the normal stresses along the subscript directions and τxy is the
shear stress in the x plane along the y direction. For a plane stress case, where the stresses are non-
zero only in a plane, say, the xy plane (that is, σz = τxz = τyz = 0), we have
εσνσ σ
ννε
ννεεσνσ σ
ννxxy x x yyyx yEEEE=^1 [ – ()] =
21
1 –+1
1 ++^1
1 –1
1 +=^1 [ – ()]or =
21
1 –1
1 +⎛
⎝
⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
⎟⎡
⎣⎢⎤
⎦⎥⎛
⎝
⎜⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
⎟⎡
⎣⎢⎤
⎦ε ννε ⎥γντ
τγ
νxyxyxy
xyxy
EE+^1
1 –+1
1 +=2 (1 + )
=
2 (1 + )(11.10k)which in matrix form becomes
= =
(1 – )10
10
00 1 –
2=σ
σ
τνν
ν
νε
ε
γx
y
xyx
y
xyE⎛⎝⎜
⎜
⎜⎞⎠⎟
⎟
⎟⎛⎝⎜
⎜
⎜⎜⎞⎠⎟
⎟
⎟⎟⎛⎝⎜
⎜
⎜⎞⎠⎟
⎟
⎟2 D (11.10l)whereD is the elasticity matrix for the plane stress case. The strain energy stored in the element then
is
SE dV d V dV dV
VT
VT
VTT T
V=^1 T
2
=^1
2
=^1
2
=^1
∫∫ ∫ 2 ∫⎧
⎨
⎩⎫
⎬
⎭ D u B DBu u B DB uThe element stiffness matrix ke is
ke B DB B DB
V= TTdV At=
∫
(11.10m)wheret is the out-of-plane thickness and the constant matrices B and D are given by Eqs. (11.10i) and
(11.10l).