Exercises 533
(b) Now consider the integral
I 2 =
∫
dx 1 dx 1 ∗...dxNdxN∗e−x
†Ax
wherexis now a complex vector. Show that
I 2 =
( 2 π)N
det(A)
.
15.2 In this problem and the next we take a closer look at the free field theory. Consider
the one-dimensional, periodic chain of particles with harmonic coupling between
nearest neighbours, and moving in a harmonic potential with coupling constantm^2.
The Lagrangian is given by
L=
1
2
∑∞
n=−∞
[φ ̇n^2 −(φn−φn+ 1 )^2 −m^2 φn^2 ].
We want to find the HamiltonianHsuch that
∫
[Dφn]e−S=〈i|e−(tf−ti)H|f〉
where
S=
∫tf
ti
L[φn(t)]dt
and the path integral
∫
[Dφn]is over all field configurations{φn}compatible withi
attiandfattf.
We use the Fourier transforms
φk=
∑
n
φneikn; φn=
∫ 2 π
0
dk
2 π
φke−ikn.
(a) Show that from the fact thatφnis real, it follows thatφk=φ∗−k, and that the
Lagrangian can be written as
L=
1
2
∫ 2 π
0
dk
2 π
{|φ ̇k|^2 −φ−k[m^2 + 2 ( 1 −cosk)]φk}.
This can be viewed as a set of uncoupled harmonic oscillators with coupling
constantω^2 k=m^2 + 2 ( 1 −cosk).
(b) In Section 12.4 we have evaluated the Hamiltonian for a harmonic oscillator. Use
the result obtained there to find
H=
1
2
∫ 2 π
0
dk
2 π
{ˆπ(k)π(ˆ −k)+φ(ˆ−k)[m^2 + 2 ( 1 −cosk)]φ(ˆk)},
where the hats denote operators;π(ˆ k)is the momentum operator conjugate to
φ(ˆk)– they satisfy the commutation relation
[ˆπ(k),φ(ˆ−k′)]=i
∑
n
eik(k−k′)n= 2 πδ(k−k′),
where the argument of the delta-function should be taken modulo 2π.