Computational Physics

(Rick Simeone) #1
4.5 Self-consistency and exchange: Hartree–Fock theory 57

therefore calculate the expectation value of the energy for an arbitrary Slater determ-
inant using the Born–Oppenheimer Hamiltonian and then minimise the result with
respect to the spin-orbitals in the determinant.
We write the Hamiltonian as follows:


H=


i

h(i)+

1


2



i,j;i=j

g(i,j) with

g(i,j)=

1


|ri−rj|
and

h(i)=−

1


2


∇i^2 −


n

Zn
|ri−Rn|

.


(4.34)


h(i)depends onrionly andg(i,j)onriandrj. Writing the Slater determinantψas
a sum of products of spin-orbitals and using the orthonormality of the latter, it can
easily be verified that this determinant is normalised, and for the matrix element of
the one-electron part of the Hamiltonian, we find (see Problem 4.3)

AS


∣∣


∣∣




i

h(i)

∣∣


∣∣



AS



=N·


(N− 1 )!


N!



k

〈ψk|h|ψk〉

=



k

〈ψk|h|ψk〉=


k


dxψk∗(x)h(r)ψk(x). (4.35)

By



dxwe denote an integral over the spatial coordinates and a sum over the
spin-degrees of freedom as usual.
The matrix element of the two-electron termg(i,j)for a Slater determinant not
only gives a nonzero contribution when the spin-orbitals in the left and right hand
sides of the inner product occur in the same order, but also forkandlinterchanged
on one side (the derivation is treated in Problem 4.3):

AS


∣∣


∣∣


∣∣



i,j

g(i,j)

∣∣


∣∣


∣∣AS



=



k,l

〈ψkψl|g|ψkψl〉−


k,l

〈ψkψl|g|ψlψk〉. (4.36)

In this equation, the following notation is used:


〈ψkψl|g|ψmψn〉=


dx 1 dx 2 ψk∗(x 1 )ψl∗(x 2 )

1


|r 1 −r 2 |

ψm(x 1 )ψn(x 2 ). (4.37)

In summary, we obtain for the expectation value of the energy:


E=


k

〈ψk|h|ψk〉+

1


2



kl

[〈ψkψl|g|ψkψl〉−〈ψkψl|g|ψlψk〉]. (4.38)
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