b. This equation requires the de Broglie relationship (also given in the AP exam booklet).
Do not mistake a vfor a n. You will also need to know J =kg m^2 /s^2.
This answer is worth 1 point.
c. This can be done as a one-step or a two-step problem. The AP test booklet gives you
the equations to solve this directly as a two-step problem. This method will be followed
here. The two equations may be combined to produce an equation that will allow you
to do the problem in one step.
Using c=ln:
Using ΔE=hn:
ΔE=(6.63 × 10 −^34 Js)(5.4 × 1014 s−^1 )(1 kJ/1000 J)(6.022 × 1023 /mol)
=2.2 × 102 kJ/mol
Give yourself 1 point for each of these answers. If you did the problem as a one-step
problem, give yourself 2 points if you got the final answer correct, or 1 point if you left out
any of the conversions.
The total for this question is 6 points, minus 1 point if any answer does not have the
correct number of significant figures.
Rapid Review
- Know the regions of the electromagnetic spectrum.
- The frequency, n, is defined as the number of waves that pass a point per second.
- The wavelength, l, is the distance between two identical points on a wave.
- The energy of light is related to the frequency by E=hn.
- The product of the frequency and wavelength of light is the speed of light: c=nl
- An orbital or wave function is a quantum mechanical, mathematical description of the
electron. - If all electrons in an atom are in their lowest possible energy level, then the atom is said
to be in its ground state. - If any electrons in an atom are in a higher energy state, then the atom is said to be in an
excited state. - The energy of an atom is quantized, existing in only certain distinct energy states.
ν==
⎛ ×
⎝
⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
c/ ⎟=×
m/s
nm
nm
m
λ
30 10
551
10
1
54 10
.^89
.^114 s−^1
λ
ν
==
×
×
⎛
⎝
⎜
⎞
⎠
⎟
×
−
−
h
m
663 10
66 10 52 1
34
24
.
..
Js
g
kg m /s^22
00
7 19 10^15
m/s
1000g
Jkg
m
⎛
⎝
⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
⎟=×. −
Spectroscopy, Light, and Electrons 145