5 Steps to a 5 AP Chemistry

330  STEP 5. Build Your Test-Taking Confidence

23.The energy required to produce a gaseous cation
from a gaseous atom in the ground state

24.The average_____is the same for any
ideal gas at a given temperature.

25.The maximum energy available for useful work
from a spontaneous reaction

26.The energy required to separate cations from
anions in an ionic solid

27.When cerium(III) acetate, Ce(C 2 H 3 O 2 ) 3 , is dis-
solved in water, the temperature increases. Which
of the following conclusions may be related to
this?

(A) The hydration energies of cerium(III) ions

and acetate ions are very low.

(B) Cerium(III) acetate is less soluble in hot

water.

(C) The solution is not an ideal solution.

(D) The heat of solution for cerium(III) acetate is

endothermic.

(E) The lattice energy of cerium(III) acetate is

very low.

28.Choose the reaction expected to have the greatest
increase in entropy.

(A) 2 H 2 (g) +O 2 (g) →2 H 2 O(g)

(B) 2 Mn 2 O 7 (l) →4 MnO 2 (s) +3 O 2 (g)

(C) C(s) +O 2 (g) →CO 2 (g)

(D) 2 Ca(s) +O 2 (g) →2 CaO(s)

(E) NH 3 (g) →NH 3 (l)

29.A certain reaction is nonspontaneous under stan-
dard conditions, but becomes spontaneous at
lower temperatures. What conclusions may be
drawn under standard conditions?

(A)ΔH<0, ΔS<0 and ΔG= 0

(B)ΔH>0, ΔS<0 and ΔG> 0

(C)ΔH<0, ΔS>0 and ΔG> 0

(D)ΔH>0, ΔS>0 and ΔG> 0

(E)ΔH<0, ΔS<0 and ΔG> 0

30.4 NO 2 (g) +Oz(g) →2 N 2 O 5 (g) ΔH= –111 kJ

Determine ΔHfor the above reaction if N 2 O 5 (s)

were formed in the above reaction instead of

N 2 O 5 (g). The ΔHof sublimation for N 2 O 5 is

54 kJ/mol.

(A)+54 kJ

(B)+219 kJ

(C)+165 kJ

(D) –219 kJ

(E) –165 kJ

31.Which of the following groups contains only

atoms that are diamagnetic in their ground state?

(A) He, Co, and Sr

(B) Zn, Mg, and Xe

(C) O, Be, and Ne

(D) Ca, Mn, and Ar

(E) As, Ba, and Rn

The following ground-state electron configu-

rations are to be used for questions 32–35:

(A) 1s^2 1p^6 2s^2 2p^3

(B) 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3dl04p^6 5s^2 4d^1

(C) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^3

(D) 1s^2 2s^2 2p^5

(E) 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6

32.It is not possible for this electron configuration to

exist.

33.A halogen has this electron configuration.

34.A transition metal atom might have this

configuration.

35.A transition metal ion could have this configuration.

The following answers are to be used for questions

36–39:

(A) Pauli exclusion principle

(B) electron shielding

(C) the wave properties of matter

(D) Heisenberg uncertainty principle

(E) Hund’s rule

36.The exact position of an electron is not known.

37.Nitrogen atoms, in their ground state, are para-

magnetic.

38.An atomic orbital can hold no more than two

electrons.

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