Chapter 6 Molecular Structure & Bonding
Figure 6.15 Hybrid orbitals and unused p orbitals The orientation of hybrid (blue) and unused p (grey) orbitals Table 6.2
Hybridization and arrangement of electron
groups around central atoms obeying the octet rule
number hybridi-
bond
π^
of groups zation
angle
bonds
2 sp 180
o^2
3 sp
2
120
o^1
4 sp
3
109
o^0
HH
H CCCH
AB
X
Z
Y
Figure 6.16 Coordinate system used in allene, C
H 3
(^4)
2sp+2p
3sp + 1p
2
4sp (no p)
3
(a)
(b)
(c)
Combining more than two orbitals involves more than two combinations, which are
done in a similar manner, but their construc
tion is beyond the scope of our discussion.
Thus, only the results are summarized here.
- Two sp hybrid orbitals
are produced by combining one s and one p orbital as shown in
Figure 6.14. They are oriented 180
o from one another as shown in Figure 6.15a. Only one p
orbital is used in their construction, so two p orbitals are available to form
π bonds. Thus, sp
hybridized atoms form two
π bonds (one triple bond or two double bonds) and have bond
angles of 180
o. Note that sp hybrid orbitals lie along the axis of the p orbital used to
construct them, so if the
σ bonds are directed along the z-axis, then the s and the p
(^) z
orbitals would be used to make the hybrid orbitals, and the p
and px
orbitals would be used y
to form
π bonds.
Three sp
2 (spoken “sp two”) hybrid orbitals
are produced by combining one s and two p
orbitals (Figure 6.15b). The three hybrid orbi
tals lie in the plane defined by the two p
orbitals used to construct them and are oriented 120
o from one another. Two p orbitals are
used in the hybridization, so only one p orbital remains to form a
π bond. Thus, sp
2
hybridized atoms have one double bond and 120
o bond angles
. If the hybrid orbitals lie in
the xy plane, then the p
and px
orbitals must be used to construct them, which leaves the y
p orbital available for z
π bonding.
3.
Four sp
3 (spoken “sp three”) hybrid orbitals
are produced by combining the s and all three p
orbitals (Figure 6.15c). There are no p orbitals available to form
π bonds, so sp
3 hybridized
atoms form only single bonds and have bond angles of 109
o.
The hybridization of an atom can be dete
rmined from the number of electron groups
around it because the number of hybrid orbitals must equal the number of electron groups. For example, an atom with four electron groups requires four hybrid orbitals, so the atom must be sp
3 hybridized. In addition, atoms that are sp or sp
2 hybridized have unused p
orbitals that are used to form
bonds, so the hybridization of an atom describes both the π
structure and bonding around the atom (Table 6.2). An atom that is sp
2 hybridized has
three electron groups, 120
o bond angles, and is involved in one
bond, while an sp π
hybridized atom has two electron groups, 180
o bond angles, and two
bonds. π
We conclude our discussion of valence bond theory by using it to explain why the
planes of the two CH
groups of allene (Figure 6.16) 2
are perpendicular. We start by
determining the hybridization of each carbon atom. The central atom is surrounded by two electron groups and is involved in two
bonds, so it is sp hybridized. If the bonding axis π
is the z-axis, then the p
orbital must be used to construcz
t the hybrid orbitals, which leaves
the p
and px
orbitals available to form the two y
bonds. Each of the terminal carbon atoms π
(C
and CA
) is surrounded by three electron groups and is involved in one B
bond, so each π
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