heat required to raise the temperature of one gram of HO by 1 2oC. 1 cal = 4.18 J.
However, a dietary calorie, which appears on packaging of common food items, is actually a kcal (1000 cal). To convert from kJ to kcal,we use the fact that 4.18 kJ = 1 kcal:(79 kJ)(1 kcal/4.18 kJ) = 19 kcal or 19 dietary calories9.4BOND ENERGIES
The
bond
or
dissociation energy
(D
) is the energy required to break one mole of bonds
in
the gaseous state
. It is always positive.
H^2(g)→
2 H(g)ΔH = +436 kJ = D(H-H)HCl(g)→ H(g) + Cl(g)ΔH = +431 kJ = D(H-Cl)Similarly, energy is always released when bonds are formed.
Table 9.2Some common bond energies (kJ/mol)
C-HH(g) + F(g)→
HF(g)ΔH= -565 kJ = -D(H-F)The enthalpy of a gas phase reaction is si
mply the difference between the amount of
energy required to break the reactant bonds and the amount of energy released when the product bonds are formed,
413 N-H391O-H463 H-H436C-F485 N-F272O-F190 H-F565C-Cl328 N-Cl200O-Cl203 H-Cl431C-Br276 N-Br243O-Br235 H-Br366C-I234O-I234 H-I299C-CΔH∼D(broken bonds) – Σ
D(formed bonds) Σ
Eq. 9.4347 N-N163C-N305 C-O358C=CEnthalpies derived from Equation 9.4 are only approximate values when tabulated bond energies are used because the bond energy depe
nds on the environmen
t of the bond, while
the values presented in tables like Table 9.2 are average values of many environments. For example, the O-H bond in F
COH is slightly weaker than in (CH 3
) 33
COH, but wewould use the tabulated, average value of 463 kJ/mol for each.
612 N=N418C=N615 C=O799C≡C820N≡N941C≡N891C≡O1072F-F 159O-O146Cl-Cl 243O=O495Br-Br 193
I-I 151* Carbon-carbon bonds can be single, double, or triple bonds, but carbonalways has four bonds to it.
† The tabulated value is -92 kJ, so this answer is off by about 5%, which
is the approximation error in this example.Example 9.3
Use the data in Table 9.2 to estimateΔH for the following reactions.a) N(g) + 3H 2(g) 2→
2NH(g). 3Bond energies depend upon both the number and types of bonds. Thus, the first thing we must do is to draw the Lewis structures of the molecules.*NNHHHHHHHNHHHNHH++The NN bond and three H-H bonds must be broken,≡and six N-H bonds must be formed.ΔH ~ D(N≡N) + 3D(H-H) - 6D(N-H) = 941 kJ + 3(436) kJ - 6(391) kJ = -97 kJ.†Chapter 9 Reaction Energetics© byNorthCarolinaStateUniversity