Chapter 11 Electron Transfer and Electrochemistry
Example 11.4
Write the anode and cathode half-reactionsand the balanced chemical equation forthe galvanic cells constructed from the following pairs of redox couples. Determine the standard cell potential for each cell.
a) Pb/Pb2+ and Zn/Zn2+^Get the reduction half-reactions and their standard reduction potentials from Table 11.1Zn2+ + 2e1-U^ZnoE
= -0.76 VPb2+ + 2e1-^ UPboE
= -0.13 VThe oxidation half-reaction is the one at morenegative potential, soZn is oxidized, andPb2+ is reduced in the cell. Both half-reactions involve two electrons, so the balancedchemical equation is the sum of the following two reactions: ZnUZn2+ + 2e1-^Anode (oxidation) half-reactionPb2+ + 2e1-^ UPbCathode (reduction) half-reactionZn + Pb2+^
→
Zn2+ + Pb Net chemical equationoE
cell(^) =
o (^) E
cathode
- E
o anode= -0.13 - (-0.76) = 0.63 Vo (^) E
cell
is positive, so the reaction is extensive.
b) Ni
2+/Ni and Ag
1+/Ag
The two relevant half-reactions and t
heir standard reduction potentials are
Ni
2+ + 2e
1-^ U
Ni
oE
= -0.23 V
Ag
1+ + e
1-U^
Ag
oE
= +0.80 V
Reverse the half-reaction at mo
re negative potential to obtain the oxidation and multiply
the Ag
1+/Ag half-reaction by 2 to make t
he number of electrons gained by Ag
1+ equal to
the number lost by the Ni. The balanced chemic
al equation for the cell is the sum of the
two reactions. Ni
U
Ni
2+ + 2e
1-^
Anode (oxidation) half-reaction
2Ag
1+ + 2e
1-^ U
2Ag
Cathode (reduction) half-reaction
Ni + 2Ag
1+^
→
Ni
2+ + 2Ag Net chemical equation
Standard reduction potentials indicate the free en
ergy of the electron(s), so multiplying a
half-reaction by some number does not
affect its standard reduction potential
. Thus,
multiplying the Ag1+/Ag half-reaction by 2 does not change the potential at which thecouple is at equilibrium. The cell potential isoE
cell=oE
cathode- E
oanode= +0.80 - (-0.23) = 1.03 V