ad/Power in a resistor: the
rate at which electrical energy is
being converted into heat.
radiating light.^7 Since the circuit oscillates at a frequency^8 of 60 Hz,
the temperature doesn’t really have time to cycle up or down very
much over the 1/60 s period of the oscillation, and we don’t notice
any significant variation in the brightness of the light, even with a
short-exposure photograph.
Thus, what we really want to know is the average power, “aver-
age” meaning the average over one full cycle. Since we’re covering
a whole cycle with our average, it doesn’t matter what phase we
assume. Let’s use a cosine. The total amount of energy transferred
over one cycle is
E=
∫
dE
=
∫T
0
dE
dt
dt,
whereT= 2π/ωis the period.
E=
∫T
0
Pdt
=
∫T
0
Pdt
=
∫T
0
IoVocos^2 ωtdt
=IoVo
∫T
0
cos^2 ωtdt
=IoVo
∫T
0
1
2
(1 + cos 2ωt) dt
The reason for using the trig identity cos^2 x = (1 + cos 2x)/2 in
the last step is that it lets us get the answer without doing a hard
integral. Over the course of one full cycle, the quantity cos 2ωtgoes
positive, negative, positive, and negative again, so the integral of it
is zero. We then have
E=IoVo
∫T
0
1
2
dt
=
IoVoT
2
(^7) To many people, the word “radiation” implies nuclear contamination. Ac-
tually, the word simply means something that “radiates” outward. Natural
sunlight is “radiation.” So is the light from a lightbulb, or the infrared light
being emitted by your skin right now.
(^8) Note that this time “frequency” meansf, notω! Physicists and engineers
generally useωbecause it simplifies the equations, but electricians and techni-
cians always usef. The 60 Hz frequency is for the U.S.
Section 10.5 LRC circuits 633