4.4Expectation 107
EXAMPLE 4.3h The joint density ofXandYis given by
f(x,y)=
{ 12
5 x(2−x−y)0<x<1, 0<y<^1
0 otherwise
Compute the conditional density ofX, given thatY=y, where 0<y<1.
SOLUTION For 0<x<1, 0<y<1, we have
fX|Y(x|y)=
f(x,y)
fY(y)
=
f(x,y)
∫∞
−∞f(x,y)dx
=
x(2−x−y)
∫ 1
0 x(2−x−y)dx
=
x(2−x−y)
2
3 −y/2
=
6 x(2−x−y)
4 − 3 y
■
4.4Expectation
One of the most important concepts in probability theory is that of the expectation
of a random variable. IfX is a discrete random variable taking on the possible values
x 1 ,x 2 ,..., then theexpectationorexpected valueofX, denoted byE[X], is defined by
E[X]=
∑
i
xiP{X=xi}
In words, the expected value ofXis a weighted average of the possible values thatXcan
take on, each value being weighted by the probability thatXassumes it. For instance, if
the probability mass function ofXis given by
p(0)=^12 =p(1)
then
E[X]= 0
( 1
2
)
+ 1
( 1
2
)
=^12
is just the ordinary average of the two possible values 0 and 1 thatXcan assume. On the
other hand, if
p(0)=^13 , p(1)=^23