Introduction to Probability and Statistics for Engineers and Scientists

(Sean Pound) #1

7.3Interval Estimates 243


SOLUTION Since


1.645

σ

n

=

3.29
3

=1.097

the 95 percent upper confidence interval is


(9−1.097,∞)=(7.903,∞)

and the 95 percent lower confidence interval is


(−∞,9+1.097)=(−∞, 10.097) ■

We can also obtain confidence intervals of any specified level of confidence. To do so,
recall thatzαis such that


P{Z>zα}=α

whenZis a standard normal random variable. But this implies (see Figure 7.1) that for
anyα


P{−zα/2<Z<zα/2}= 1 −α

As a result, we see that


P

{
−zα/2<


n

(X−μ)
σ

<zα/2

}
= 1 −α

or


P

{
−zα/2

σ

n

<X−μ<zα/2

σ

n

}
= 1 −α

or


P

{
−zα/2

σ

n

<μ−X<zα/2

σ

n

}
= 1 −α

That is,


P

{
X−zα/2

σ

n

<μ<X+zα/2

σ

n

}
= 1 −α

Area = –

−za/2 0 za/2

a
Area = – 2
a
2

FIGURE 7.1 P{−zα/2<Z<zα/2}= 1 −α.

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