Introduction to Probability and Statistics for Engineers and Scientists

(Sean Pound) #1

9.3Distribution of the Estimators 357


=

α


i

(xi−x)+β


i

xi(xi−x)

i

xi^2 −nx^2


[∑
i

xi^2 −x


i

xi

]


i

x^2 i−nx^2

since


i

(xi−x)= 0


ThusE[B]=βand soBis an unbiased estimator ofβ. We will now compute the variance
ofB.


Var(B)=

Var

(n

i= 1

(xi−x)Yi

)

(n

i= 1

xi^2 −nx^2

) 2

=

∑n
i= 1

(xi−x)^2 Var(Yi)
(n

i= 1

xi^2 −nx^2

) 2 by independence

=

σ^2

∑n

i= 1

(xi−x)^2

(n

i= 1

xi^2 −nx^2

) 2

=

σ^2
∑n
i= 1

xi^2 −nx^2

(9.3.2)

where the final equality results from the use of the identity


∑n

i= 1

(xi−x)^2 =

∑n

i= 1

xi^2 −nx^2
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