Introduction to Probability and Statistics for Engineers and Scientists

(Sean Pound) #1

10.6Two-Way Analysis of Variance with Interaction 467


Namely,


reject H 0 int if

SSint/(n−1)(m−1)
SSe/nm(l−1)

>F(n−1)(m−1),nm(l−1),α
do not reject H 0 int otherwise

Alternatively, we can compute thep-value. IfFint=v, then thep-value of the test of the
null hypothesis that all interactions equal 0 is


p-value=P{F(n−1)(m−1),nm(l−1)>v}

If we want to test the null hypothesis


H 0 r:αi=0,i=1,...,m

then we use the fact that whenH 0 ris true,Xi..is the average ofnlindependent normal
random variables, each with meanμand varianceσ^2. Hence, underH 0 r,


E[Xi..]=μ, Var(Xi..)=σ^2 /nl

and so


∑m

i= 1

nl

(Xi..−μ)^2
σ^2

is chi-square withmdegrees of freedom. Thus, if we let


SSr=

∑m

i= 1

nl(Xi..−ˆμ)^2 =

∑m

i= 1

nl(Xi..−X..)^2

then, whenH 0 ris true,


SSr
σ^2

is chi-square withm−1 degrees of freedom

and so


SSr
m− 1

is an unbiased estimator ofσ^2

Because it can be shown that, underH 0 r,SSeandSSrare independent, it follows that
whenH 0 ris true


SSr/(m−1)
SSe/nm(l−1)

is anFm− 1 ,nm(l−1) random variable
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