one is larger. Here we don’t have enough evidence to conclude that Delayed is different
from Nonsmoking, but we dohave enough evidence (i.e., power) to conclude that there is a
significant difference between Active and Nonsmoking. This kind of result occurs fre-
quently with multiple-comparison procedures, and we just have to learn to live with a bit
of uncertainty.
13.7 Power Analysis for Factorial Experiments
Calculating power for fixed-variable factorial designs is basically the same as it was for
one-way designs. In the one-way design we defined
and
where , k 5 the number of treatments, and n 5 the number of observa-
tions in each treatment. In the two-way and higher-order designs, we have more than one “treat-
ment,” but this does not alter the procedure in any important way. If we let , and
, where represents the parametric mean of Treatment (across all levels of
B) and represents the parametric mean of Treatment (across all levels of A), then we
can define the following terms:
and
Examination of these formulae reveals that to calculate the power against a null hypothesis
concerning A, we act as if variable Bdid not exist. To calculate the power of the test against
a null hypothesis concerning B, we similarly act as if variable Adid not exist.
Calculating the power against the null hypothesis concerning the interaction follows
the same logic. We define
where is defined as for the underlying structural model ( ).
Given we can simply obtain the power of the test just as we did for the one-way
design.
Calculating power for the random model is more complicated, and for the mixed model
requires a set of rather unrealistic assumptions. To learn how to obtain estimates of power
with these models, see Winer (1971, p. 334).
In certain situations a two-way factorial is more powerful than are two separate one-
way designs, in addition to the other advantages that accrue to factorial designs. Consider
two hypothetical studies, where the number of participants per treatment is held constant
across both designs.
fab
abij abij=m2mi.2m.j1mij
fab=f¿ab 1 n
f¿ab=
B
aab
(^2) ij
abs^2 e
fb=f¿b 2 na
f¿b=
B
ab
(^2) j
bs^2 e
fa=f¿a 2 nb
f¿a=
B
aa
2
j
as^2 e
m.j Bj
bj=m.j2m mi. Ai
ai=mi.2m
gt^2 j =g(mj2m)^2
f=f¿ 2 n
f¿=
B
at
2
j
ks^2 e
Section 13.7 Power Analysis for Factorial Experiments 429