1000 Solved Problems in Modern Physics

(Romina) #1

6.1 Basic Concepts and Formulae 315


Inverse transformations


x=γ(x′+νt′) (6.12)
y=y′ (6.13)
z=z′ (6.14)

t=γ

(

t′+
νx′
c^2

)

(6.15)

with


γ=

1


(1−β^2 )

=

1


(1−ν^2 /c^2 )

(6.16)

and


β=

ν
c

(6.17)

Transformation matrix


The Lorentz transformations (6.8), (6.9), (6.10), and (6.11) can be condensed in the
matrix form


X′=ΛX (6.18)

whereX=





x 1
x 2
x 3
x 4




⎦ and X

′=





x 1 ′
x 2 ′
x 3 ′
x 4 ′




⎦ (6.19)

are the column vectors with components


x 1 =x,x 2 =y,x 3 =z,x 4 =τ=ict (6.20)
x 1 ′=x′,x 2 ′=y′,x′ 3 =z′,x′ 4 =τ′=ict′ (6.21)

withi=



−1, andΛis an orthogonal matrix

Λ=





γ 00 iβγ
01 00
00 10
−iβγ 00 γ




⎦ (6.22)
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