Optimal stopping
As we have already seen ifT=n+ 1 ,thenSn(T)=fmaxknξkag.
Now letT=n+2 that is two periods are still ahead. We must show that
Sn=Sn(T)Sn(T+^1 ).Vn$maxmaxknξk,E(Vn 1 ++^1 j Fr n)=
=max0
@max
knξk,E
maxmaxkn+ 1 ξk,E(Vn+ 12 +jFrn+^1 )j Fn1 +r1
A.
As
max
kn+ 1ξkmax
knξka
using the induction hypothesis that if one periods left then the
fxjxagis the stopping regionmaxkmaxn+ 1 ξk,E(Vn+^2 j Fn+^1 )
1 +r=kmaxn+ 1 ξk.