3.1 SINUSOIDAL STEADY-STATE PHASOR ANALYSIS 121
Solution
−
+
V
(a)
Inductive
load
Capacitor added (in parallel)
for power factor correction (improvement)
C
Source
SL =
P
P = PS = PR = 100 kW
QL = 75 kVAR = P tan φL
(b)
QC = −42.13
kVAR
QS = 32.87
kVAR
1002 + 752 = 125 kVA
cos φL
cos−^1 0.95 = 18.19° = φS
cos
−^1 0.8 = 36.87
° = φL
=
Figure E3.1.9(a)Circuit.
(b)Power triangles.
The circuit and the power triangles are shown in Figure E3.1.9. The real powerP=PS=PR
delivered by the source and absorbed by the load is not changed when the capacitor (considered
ideal) is connected in parallel with the load. After the capacitor is connected, noting thatQCis
negative,QS=QL+QC=100 tan(18.19)=32.87 kVAR,
SS=
P
cosφS
=
100
0. 95
= 105 .3kVa
(Note that the power factor correction reduces the current supplied by the generator signifi-
cantly.) So
QC=QS−QL= 32. 87 − 75 =− 43 .13 kVAR
Thus the capacitor is delivering 43.13 kVAR to the system (or absorbing negative kVAR). Then
Vrms^2
XC
=
1002
XC
=− 43. 13 × 103 or XC=− 0. 232 =−
1
ωC
or
C=
1
2 π× 60 × 0. 232
= 0 .0114 F or 11 .4mF
Fourier Series
The phasor method of circuit analysis can be extended (by using the principle of superposition)
to find the response in linear systems due to nonsinusoidal, periodic source functions. A periodic
function (t) with periodTcan be expressed inFourier series,
f(t)=
∑∞
n= 0
ancosnωt+
∑∞
n= 1
bnsinnωt (3.1.45)