172 TIME-DEPENDENT CIRCUIT ANALYSIS
requests frequency analysis with 20 points per decade, which is usually a suitable value, starting at
10 Hz and ending at 1 MHz. Note that the frequencies would be uniformly spaced on a logarithmic
frequency scale.
EXAMPLE E3.5.3
Develop a PSpice program and use PROBE to obtain Bode plots of the magnitude and phase of
the transfer functionV ̄out/V ̄infor the high-pass filter circuit shown in Figure E3.5.3(a) along with
node numbers. This filter is to pass components above 1 kHz and reject components below 1 kHz.
−
+
−
+
Vin = 1 ∠ 0 ° Vout
(a)
R = 314.1 Ω
L = 50 mH
1 2 C^ = 0.507 μF 3
0
Figure E3.5.3(a) High-pass
filter circuit. (b) Magnitude
Bode plot.(c)Phase plot.
|H(f)|
dB
(b)
100 Hz
− 60
− 80
− 40
− 20
0
20
10 Hz 1.0 kHz 10 kHz 100 kHz
(c)
100 Hz
180 °
0 °
45 °
90 °
135 °
10 Hz 1.0 kHz 10 kHz 100 kHz
Solution
The transfer functionH(f) ̄ =V ̄out/V ̄inis numerically equal to V(3) since the amplitude ofV ̄in
is given as 1 V. Thus to obtain a plot of the transfer-function magnitude in decibels, the PROBE
menu commands can be used to request a plot of VDB (3). A Bode plot of the transfer function
can be obtained by requesting a plot of VP (3). The program is as follows:
EXAMPLE E3.5.3
THE CIRCUIT DIAGRAM IS SHOWN IN FIGURE E3.5.3(a)
VIN10AC1
R 1 2 314.1
C 2 3 0.507 UF
L3050MH