Variables
What is the strategy?
- Draw a free-body diagram.
- Use trigonometry to calculate the net force on the ball along each axis.
- Use Newton’s second law to find the acceleration of the ball along each axis. The mass of the ball is not given, but you can determine it
because you are told its weight. We do this in the variables table.
Physics principles and equations
Newton’s second law
ȈF = ma
Step-by-step solution
We begin by calculating the net force along the x axis.
We next calculate the force along the y axis. In this case, there are two forces to consider.
Now we calculate the acceleration along the x axis, using Newton’s second law.
We calculate the acceleration along the y axis.
The acceleration values may seem very large, but this is the acceleration during the brief moment the bat is in contact with the ball.
x component y component
weight 0 mg sin 270° = í1.40 N
force F cosș F sinș
acceleration ax ay
force F = 262 N
angle ș = 60.0°
mass m = mg/g = (1.40 N) / (9.80 m/s^2 ) = 0.143 kg
Step Reason
1. ȈFx = F cos ș net force along x axis
2. ȈFx = (262 N)(cos 60.0°) x component of force
3. ȈFx = 131 N evaluate
Step Reason
4. ȈFy = F sin ș + (í1.40 N) net force along y axis
5. enter values
6. ȈFy = 225 N evaluate
Step Reason
7. ȈFx = max Newton's second law
8. ax =ȈFx/m solve for ax
9. ax = (131 N) / (0.143 kg) enter values from step 3 and table
10.ax = 916 m/s^2 division
Step Reason
11.ȈFy = may Newton's second law
12.ay =ȈFy/m solve for ay
13.ay = (225 N)/(0.143 kg) enter values from step 6, table
14.ay = 1570 m/s^2 division
(^106) Copyright 2007 Kinetic Books Co. Chapter 05