Equation 2 shows how to solve for the range. The horizontal displacement of the ball
equals the product of its horizontal velocity and the elapsed time. Since its horizontal
velocity does not change, it equals the initial horizontal velocity. Together, the two
equations describe the flight of a projectile that is fired horizontally.Projectile flight time
vyi = initial y velocity
ǻy = vertical displacement
ay = í9.80 m/s^2
t = time when projectile hits ground
Projectile range
ǻx = vxt
ǻx = horizontal displacement
vx = horizontal velocity
(^70) Copyright 2000-2007 Kinetic Books Co. Chapter 04