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FACTORIZATION Factorization The process of expressing a polynomial as the product of two or more simpler polynomials is called ...
Solution: 3-7-5 3 9 -42 19 70 25 9 6 -7 -42 19 -42 49 6 -14 -5 -30 70 25 -30 70 25 0 Therefore, 9 x^4 − 42 x^3 + 19 x^2 + 70 x+ ...
Linear equation in one variable An algebraic equation with a single variable whose power is equal to 1 is termed as a linear eq ...
Solution of simultaneous linear equations The numerical values of the two unknown variables in a pair of linear equations in tw ...
Finite sequence If the last term of a sequence is known then it is called a finite sequence. The idea may be taught orally supp ...
1, 4, 7, 10, ... The difference between the second and the first term is 4 – 1 = 3. The difference between the third term and th ...
Decreasing sequence If the value of ‘d’ the common difference is negative, then the sequence is a decreasing sequence. Eg. : 1 ...
n = 12 Sum of A.P., 2 + 4 + 6 + ... + 24 =^122 ()^2 +^24 = 6 (26) 2 + 4 + 6 + ... + 24 = 156 The idea needs to be explained thro ...
= 3 x 3 x 3 x 3 x 3 = 243 Finite GP A GP whose last term is known is said to be a finite GP. Eg. : 1, 2, 4, 8, 16, ... 256 Here ...
12 +2^2 +3^2 +4^2 +5^2 +...+n^2 = n (n+^16 ) (^2 n+^1 ) where ‘n’ is the number of terms in the sequence. Sum of the cubes of t ...
Write the product 2 below 5 and add. The sum is 7. Multiply 7 with 2 and write the product 14 below 6. The sum is 20. Hence in t ...
Dividing P(x) by x+2 Then P(-2)= (-2)^2 +5(-2)+6 = 4-10+6 = 10-10 P(-2) = 0 ∴ x+2 is a factor of x^2 +5x+6 Solution of a quadra ...
b^2 – 4ac >0 then the roots are real and distinct. b^2 – 4ac =0 then the roots are real and equal. b^2 – 4ac <0 then the r ...
Module 68 : Logarithm LOGARITHM Logarithm The concept of logarithm was introduced by a Scottish mathematician John Napier (1550 ...
Therefore, x = 3 log 5 125 = 3 The idea of logarithm is to be explained with examples prepared in braille format. Laws of logar ...
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Parts of a circle Centre, radius, diameter, chord, segment, arc, sector and circumference are the different parts of a circle. ...
The procedure followed in the above case may be followed as it is, and when the child is allowed to measure the lengths of the s ...
Provide the child with a circular ring along with a piece of thread. Explain the idea orally and then allow the child to measure ...
Perimeter of a semi circle Perimeter of a semi circle = Half of the circumference of the circle + Twice the radius = π r + 2r u ...
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