whether or not the first two digits are smaller than the first two digits of the dividend.
If the divisor is bigger, do not leave a column. Otherwise leave a column. Most of the
time, you need not skip the columns after the setting of the first digit of the quotient.f) In this problem, consider the divisor 28 and 21 of the dividend 218. Since 28 is
greater than 21, do not leave a column. The quotient should be set to the immediate
right of the already set quotient 1.
g) Now consider 2 of the divisor. Add 1 mentally. Ask how many 3’s in 21? By saying,
7, set the 7 to the immediate right of the quotient 1. Now multiply 7 5 28 and
subtract that value from 218. You will be left with 22.
h) Now consider 228. By the above mentioned method, set 7 to the immediate right of
17, the quotient already set in the abacus. Now multiply 7 5 28 and subtract the
value 196 from 228. You get the remainder as 32 which is greater than the divisor.
i) Don’t worry. Ask : how many 28’s in 32. By saying 1, add (no new setting) that with
the 7 which is set just now, that is the third digit of the quotient. Now it becomes 8.
This means your last digit of the quotient is altered as 8 instead of 7. Now subtract
28 from 32. You get 178 as the quotient and 4 as REMAINDER.
j) Note that the numbers of the remainder appear in the appropriate columns.
EXERCISE1) 4552 ÷ 48
2) 5436 ÷ 54
3) 6844 ÷ 37
4) 7453 ÷ 38
5) 8436 ÷ 43
6) 9834 ÷ 24
7) 2832 ÷ 23
8) 5428 ÷ 24
9) 9009 ÷ 34
10) 8819 ÷ 26