remainder. That means, square root of 324 is 18 and 324 is a perfect
square.You will really feel that this is a long process. But this can be simplified.
IN THIS PROBLEM YOU ASSUMED A MAXIMUM OF 9 AS THE QUOTIENT. ALWAYS
REDUCE 1 from this and set it as the quotient. Most of the time, this value
will be true. In case you get more remainder, add 1 to the quotient and
subtract the number from the quotient as in the case of division.
You will find this easy when you solve many problems.B. Example : 1296
a) Group this as 12 and 96
b) Highest perfect square in 12 is 9. Thus set the square root of 9 which is 3 in
the left side of the number 12.
c) Subtract 9 from 12. The remaining value is 396.
d) Double the 3 and set the 6 in the extreme left. Now ask : how many 6’s in 39.
You get a maximum of 6. You can select this as the second digit of the square
root. To be on the safe side, set 5 to the right of 6 and make it 65. Set 5 to
the right of 3 and make it 35.
e) Multiply 5 with 65 and subtract from 396. That is subtract 5×65=325 from
- You get remainder as 71 which is greater than 65. Subtract 65 from 71.
You are left with 6.
f) Please look at the last digit of the square root. It is 6. The remainder is also
- This is nothing but the difference between the multiplication of 5 of the
35 with 6, i.e., 5×6=30 and the multiplication of the new additional number
in the square root, i.e., 6×6=36. This happens only when your assumed
quotient in the case of square root is less than that of the actual quotient.
When the actual quotient is same as the assumed quotient, this will not
happen.