Principles of Mathematics in Operations Research

(Rick Simeone) #1
170 12 Differentiation

Remark 12.1.4 The converse is not true. One can construct continuous
functions which fail to be differentiate at isolated points.

Let us state some properties: Suppose / and g are denned on [a, b] and are
differentiable at x G [a,b]. Then, f + g, f • g and f/g are differentiable at x,
and
(a) (f + gy(x) = f'(x)+g'(x).
(b) (f-gy(x) = f'(x)g(x) + f(x)g>(x).
(c) (f/g)'(x) = /'(*)g(*)-/(«)g'(«), g{x) + o.

(d) Chain Rule: If h(t) = (g°f)(t) = g(f{t)), a < t < b, and if/ is continuous
at [a, b], f exists at x £ [a,b], g is defined over range of / and g is
differentiable at f(x). Then, h is differentiable at x and


h'(x) = g'(f(x))f(x).


Example 12.1.5 (Property (c)) The derivative of a constant is zero. If
f(x) — x then f'(x) — 1. // f(x) — x • x = x^2 then f'(x) — x + x = 2x by
property (b). In general, if f(x) = xn then f'(x) = nxn~^1 , n € N. If f{x) =
i = x~l then f'(x) = ^ = -x~^2. In this case, x ^ 0. if f(x) = x~n, n E N
then f'(x) = — nx~ -("+^1 ). Thus, every polynomial is differentiable, and every
rational function is differentiable except at the points where denominator is
zero.
Example 12.1.6 (Property (d)) Let

/(*){


X sin -, x ^ 0


0, x = 0

Then, f'(x) = sin \ - \ cos A, x ^ 0. At x = 0, A is no* de/med /(t|l^0) =
sin j. yls £ —>• 0, £/ie Kraii does not exist, thus /'(0) does not exist.

12.2 Mean Value Theorems

Definition 12.2.1 Let f : [a,b] H-» K. We say f has a local maximum at
peXif35>0 B f{q) < f(p), V</ G X with d{p,q) < 5. Local minimum is
defined similarly.


Theorem 12.2.2 Let f : [a,b] i-> K. /// has a local maximum (minimum)
at x £ (a,b) and if f'(x) exists, then f'(x) = 0.


Proof. We will prove the maximum case:
Choose S as in the definition: a < x — 5<x<x + 5<b.
lix-8<t<x, then mtZfJx) > 0. Let t -> x => /'(a:) > 0.


If x < t < x + (5, then f{t)tZfx{x) < 0. Let t -> oo => /'(a;) < 0.
Thus, /'(x) = 0. D

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