8 1 Introduction
Proof. Base: n = 1 = -j-1-
Hypothesis: n = j, ELi * = =L^-
Conciusion: n = j + 1, Efc=i-J + l & I. _ (.7 + D(J+^2 )
Thus, l + 2 + --- + n = £?_,fc=^i. D
1> = (i+1) [1+f] _ (j+l)(j+2) — 2
fc=l'
1.3.3 Contradiction Method
When we examine the operation table for A =*• B in Table 1.2, we immediately
conclude that the only circumstance under which A =4- B is not correct is when
A is true and B is false.
Contradiction
Proof by Contradiction assumes the condition (A is true B is false) and tries
to reach a legitimate condition in which this cannot happen. Thus, the only
way A =$• B being incorrect is ruled out. Therefore, A => B is correct. This
proof method is quite powerful.
Proposition 1.3.
n 6 N, n is even =$• n is even.
Proof. Let us assume that n 6 N, n^2 is even but n is odd. Let n = 2k -1, A; 6
N. Then, n^2 = 4k^2 - 4/c + 1 which is definitely odd. Contradiction. •
Contraposition
In contraposition, we assume A and B and go forward while we assume A
and come backward in order to reach a Contradiction. In that sense, con-
traposition is a special case of Contradiction where all the effort is directed
towards a specific type of Contradiction (^4 vs. A). The main motivation under
contrapositivity is the following:
A=> B = AVB = (A\/ JB) V A = (A/\B)^> A.
One can prove the above fact simply by examining Table 1.2.
Table 1.2. Operation table for some logical operators.
A
T
T
F
F
A
F
F
T
T
B
T
F
T
F
B
F
T
F
T
A^B
T
F
T
T
Av B
T
F
T
T
AAB
F
T
F
F
A/\B^ A
T
F
T
T