Solutions 247
D=(0,8,10)
x3 A
,V,Y, V
72>
Fig. S.12. Exercise 8.1: Primal and dual polyhedra
Thus, S3 enters.
B-iNss =
10-1
01 0
00 1
0
0
-1
=
1
0
-1
•Si
X3
x 2
Thus, «i leaves.
New partition is XB — (sz,X3,X2)T, x?j = (xi,S2,s)T. Then,
£ =
OOll
0 10
-1 0 1
J5-^1
"10
01
1 0
-1"
0
0