Section 5.19 Stereochemistry of Electrophilic Addition Reactions of Alkenes 223
- Stereochemistry of Hydrogen Addition
In a catalytic hydrogenation, the alkene sits on the surface of the metal catalyst and
both hydrogen atoms add to the same side of the double bond (Section 4.11). There-
fore, the addition of to an alkene is a syn addition reaction.
If addition of hydrogen to an alkene forms a product with two asymmetric carbons,
only two of the four possible stereoisomers are obtained because only syn addition can
occur. (The other two stereoisomers would have to come from anti addition.) One
stereoisomer results from addition of both hydrogens from above the plane of the dou-
ble bond, and the other stereoisomer results from addition of both hydrogens from
below the plane. The particular pair of stereoisomers that is formed depends on
whether the reactant is a cis-alkene or a trans-alkene. Syn addition of to a cis-
alkene forms only the erythro enantiomers. (In Section 5.8, we saw that the erythro
enantiomers are the ones with identical groups on the same side of the carbon chain in
the eclisped conformers.)
H 2
Pt
HH
C C
addition of H 2 is a syn addition
HH
CC
H 2
Fischer projections of the stereoisomers of the product
CH 2 CH 3
HH
Br Br
CH 3
CH 3
CH 2 CH 3
CH 2 CH 3
CH 3
CH 3
CH 2 CH 3
CH 2 CH 3
H CH 3
CH 3 Br
CH 2 CH 3
CH 2 CH 3
Br CH 3
CH 3 H
CH 2 CH 3
HBr CH 3 CH 2 CH CCH 2 CH 3
CH 3 CH 3
Br
H 2 O 2
+
CH 3 CH 2 CH 2 CH 3
H 3 C
cis-3,4-dimethyl-3-hexene 3-bromo-3,4-dimethylhexane
new asymmetric
carbons
CH 3
CC * *
Br
CH 3
C C
CH 2 CH 3
CH 3 CH 2 H
H
Br
CC
CH 3 CH 2
CH 3 CH 2 CH 3
H
CH 3
Br
C C
CH 2 CH 3
CH 3 CH 2 CH 3
H
CH 3
CH 3
CC
CH 3 CH 2
CH 3 CH 2 CH 3
H
Br
perspective formulas of the stereoisomers of the product
HH
CC H
+
+ =
H 3 C CH 2 CH 3 CH 2 CH 3
cis-2,3-dideuterio-
2-pentene
erythro enantiomers
Fischer projections
erythro enantiomers
perspective formulas
(eclipsed conformers)
erythro enantiomers
perspective formulas
(staggered conformers)
D D
Pt/C
H 2
CH 3
HD
HD
CH 2 CH 3
CH 3
DH
DH
CH 2 CH 3
H 3 C CH 2 CH 3
D D
CC
HH
C C
H 3 C
D D
CH 2 CH 3 H
+
H 3 C
D D
CC
HH
C C D
D CH 2 CH 3
H 3 C